我想检查occupanysequenceorder
的每个实例是否与为此字段输入的请求相匹配。当我执行log.error
时,它会输出:
ERROR:[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
ERROR:1
因此,当请求输入1时,它意味着在列表中所有实例需要等于1,它在上面执行。但是,当我执行断言时:
assert roominfo.occupancySequenceOrder.flatten() == occupancysequenceorder_request
它抛出一个错误的断言,我不确定为什么?如何通过执行相关检查来获取脚本断言。我将断言改为
assert roominfo.occupancySequenceOrder.flatten().contains(occupancysequenceorder_request)
它已通过,但我不确定是否确实进行了正确的检查,以确保occupanysequenceorder
的每个实例都与输入的请求相匹配。
以下是代码:
json.testregions.each { roominfo ->
log.error roominfo.occupancySequenceOrder.flatten()
log.error occupancysequenceorder_request
assert roominfo.occupancySequenceOrder.flatten() == occupancysequenceorder_request
}
答案 0 :(得分:1)
从here
查看OP的其他问题及其数据您可以在Script Assertion
下面尝试:
//Check if the response is not empty
assert context.response, "Response is empty or null"
//Modify the value of the quest or read it thru properties if you want
def requestValue = 1
def json = new groovy.json.JsonSlurper().parseText(context.response)
json.regions.each { region ->
region.hotels.each { hotel ->
hotel.roomInformation. each { room ->
assert room.occupancySequenceOrder == requestValue, "Value did not match for room ${room.hotelRoomId}"
}
}
}
答案 1 :(得分:0)
而是尝试:
roominfo.occupancySequenceOrder.every { it == 1 }
flatten()
对平展List
无效。
您也可以尝试:
roominfo.occupancySequenceOrder.unique() == [1]
如果您想比较列表。