如何删除列表中两个值的所有出现？

Question

我想使用一行删除列表中两个值的所有出现。我尝试了filter + lambda方法和列表理解，但它没有按照我期望的方式工作。

类似的东西：

s2 = [0, 0, 3, 11, 14, 17, 18, 18]
# I want to remove all 0 and 18 from s2 list
# i.e. I want output: s2_filter = [3, 11, 14, 17]

s2_filter = filter (lambda a: a != 0 or 18, s2)
>>> s2 = [0, 0, 3, 11, 14, 17, 18, 18] # not what I'm expecting

s2_filter = [i for i in s2 if i != 0 or 18]
>>> s2 = [0, 0, 3, 11, 14, 17, 18, 18] # not what I'm expecting

我想or有问题，但我无法弄清楚我应该怎么写这个。

你能帮忙吗？

Answer 1

如果i不在非理想列表中，您可以过滤掉：

s2 = [0, 0, 3, 11, 14, 17, 18, 18]
s2_filter = [i for i in s2 if i not in [0, 18]]
s2_filter
[3, 11, 14, 17]