Question

我只想解析一个xml文件，就像

一样

 <?xml version="1.0" encoding="UTF-8"?><Significant Major="3" Minor="0" Revision="1" xmlns="urn:reuterscompanycontent:significantdevelopments03"><RepNo>0091N</RepNo><CompanyName Type="Primary">XYZ</CompanyName><Production Date="2017-02-23T18:10:39" /><Developments><Development ID="3534388"><Dates><Source>2017-02-23T18:18:32</Source><Initiation>2017-02-23T18:18:32</Initiation><LastUpdate>2017-02-23T18:23:26</LastUpdate></Dates><Flags><FrontPage>0</FrontPage><Significance>1</Significance></Flags><Topics><Topic1 Code="254">Regulatory / Company Investigation</Topic1></Topics><Headline>FTC approves final order settling charges for Abbott's deal with St. Jude Medical</Headline></Development></Developments></Significant>

我只想解析Development标记并解析其每个嵌套标记我有以下代码：

import xml.etree.cElementTree as ET
tree = ET.ElementTree(file='../rawdata/SigDev_0091N.xml')

#get the root element
root = tree.getroot()

#print root.tag, root.attrib

for child in root:
#print child.tag, child.attrib
    name = child.tag
    print name
    print 'at line 13'
    if name is 'Developments':
        print 'at line 15'
        for devChild in name['Developments']:
            print devChild.tag,devChild.attrib

它不会进入if块，我不知道为什么？

Answer 1

检查false始终返回child.tag，{xmlns}tagname将返回strip()格式的值。

对于你的情况：

name = {urn：reuterscompanycontent：significantdevelopments03}发展

您可以参考此question的答案。

简单字符串方法find()，split()，re或{{1}}可以帮助您跳过命名空间进行比较。

相关的Python文档：https://docs.python.org/2/library/xml.etree.elementtree.html#parsing-xml-with-namespaces

在python中解析一个嵌套标签的xml文件

1 个答案: