Question

我已经获得指令“编写一个程序，要求用户输入质量和速度值，然后调用 kinetic_energy 函数来获得对象的动能。”

我编写的代码在逻辑上是正确的，但我想知道我的语法是否向后，然后说明中描述了什么。我相信我的 main 函数正在计算结果，只是将其传递给 kinetic_energy 函数。我相信说明书要求以相反的顺序完成。如果我的假设是正确的，我将如何重写它以遵守指示？

#Gets the inputs from the user for mass and velocity
def main():
    mass = int(input('Please enter the objects mass in kilograms: '))
    velocity = int(input('Please enter the objects velocity in meters per second: '))

#Calculates the kinetic energy
    kinetic_energy(ke = .5 * mass * velocity ** 2)

#Calculates the kinetic energy
def kinetic_energy(ke):
    print ('The amount of kenetic energy is ',format(ke,',.2f'),sep='')

main()

Answer 1

您将kinetic_energy定义为一个函数，它接受两个参数，质量和速度，然后返回计算值：

def kinetic_energy(m, v):
    return .5 * m * v ** 2

然后从main调用该函数：

def main():
    mass = int(input('Mass in kilograms: '))
    velocity = int(input('Velocity in m/s: '))
    ke = kinetic_energy(mass, velocity)
    print('Kinetic energy is {.2f}'.format(ke))

main()

Answer 2

通常，您编写的功能是＆＃34; work＆＃34;。

因此，如果你有一个var indexName = "index-name"; var mustClauses = new List<QueryContainer>(); var filterClauses = new List<QueryContainer>(); mustClauses.Add(new TermQuery { Field = new Field("description"), Value = "white" }); filterClauses.Add(new NumericRangeQuery { Field = new Field("price"), LessThanOrEqualTo = 3000, GreaterThanOrEqualTo = 2000 }); var searchRequest = new SearchRequest<Product>(indexName) { Size = 10, From = 0, Query = new BoolQuery { Must = mustClauses, Filter = filterClauses } }; var searchResponse = client.Search<Product>(searchRequest);函数，那么你可以使用该函数来完成比打印更多的工作。

所以，更适合重写你的东西：

kinetic_energy

将两个值从用户输入传递给函数并获取结果

2 个答案: