Question

这个for循环确实存在准确的问题（我遇到了问题？）。

- 使用GmailApp.getInboxThreads（k，max）[k];但这跳过了其他所有线程。（你能告诉我为什么吗？）

- 这只有在k = 0且max = 100时才有效。如果我尝试做k = 100和max = 100，我会得到一组空白数据。执行日志显示，当k = 100且max = 100时，完全跳过for循环。

提前感谢您的帮助!!!

function newEmailAddressList(){

 var ss = SpreadsheetApp.getActiveSpreadsheet();
 var sheet = ss.getSheetByName("NewEmails");
 var range = sheet.getRange("A3:Q");
 var varRange = sheet.getRange("A2:G2");
 var addrA = [];



 range.clearContent(); //May need to change this to my delete function to speed things up.

 var contact = ContactsApp.getContacts();       //var contact = ContactsApp.getContacts();

 //////////

  for(var i = 0; i < contact.length; i++){      //for(var i = 0;i < contact.length;i++){

   //var addrA = [];                             //var addrA = []; This can't be here. It is not global or accessable if it is in this loop and the other global version doesn't access it apparently

   var addresses = contact[i].getEmails();     // var addresses = contact[i].getEmails();  

   for(var j = 0;j < addresses.length; j++){    //for(var j = 0;j < addresses.length;j++) {                           

      var address = addresses[j].getAddress();                //   s += addresses[j].getAddress() + br;

     addrA.push(address);                       //   
    }; 


}; /////////////////////AT THIS POINT CONTACTS ARRAY IS COMPLETE/////////////////////////

 var joinAddr = addrA.join();
 //var lowerAddr = joinAddr.toLowerCase();

 var startingEmail = sheet.getRange("C2").getValue();
 var numEmails = sheet.getRange("E2").getValue();

 var max = numEmails;



 for (var k = startingEmail; k<max; ++k){

 var threads = GmailApp.getInboxThreads()[k]; //get max threads starting at most recent thread
 var messages = threads.getMessages()[0];

       var sndr; 
       var rcpnt;
       var srAry = [];



       var sndr = messages.getFrom().replace(/^.+<([^>]+)>$/, "$1"); //http://stackoverflow.com/questions/26242591/is-there-a-way-to-get-the-specific-email-address-from-a-gmail-message-object-in      
       var sndrLower = sndr.toLowerCase;

       var rcpnt = messages.getTo().replace(/^.+<([^>]+)>$/, "$1");
       var rcpntLower = rcpnt.toLowerCase;

       var cc = messages.getCc().replace(/^.+<([^>]+)>$/, "$1");
       var ccLower = cc.toLowerCase;

       //srAry.push(sndr);
       //srAry.push(rcpnt);
       //srAry.push(cc);



    var isIn = joinAddr.search(sndr || rcpnt);

     if(isIn == -1){

      var instance = k;
      var dat = messages.getDate();
      //var sndr = messages.getFrom();
      //var rcpnt = messages.getTo();
      var sub = messages.getSubject();
      var msg = messages.getPlainBody();


      var info = [instance,dat,sndr,rcpnt,cc,sub,msg];

       sheet.appendRow(info); //appendRow only works with sheet class not range class



};//else{ break;  };

};

//Browser.msgBox(("Here are your New Contacts from Emails "k" through "k + max"!"));

getContactGroups();

};

Answer 1

请注意，for循环严格等于while循环：

//for (/*Init*/; /*Cond*/; /*Step*/) { /*Action*/ }
//stricty equal to :
/*Init*/;
while (/*Cond*/) {
    /*Action*/;
    /*Step*/;
}

因为k = max = 100，那么k < max返回false，所以你不要进入循环。如果你想保持k = max = 100，那么你应该使用k <= max（小于或等于）或do-loop。

Answer 2

我认为您在使用Gmail API或如何运行for循环时遇到问题。

关于第一个问题，请查看Gmail API doc

您可以使用：

getInboxThreads()
//OR 
getInboxThreads(start, max)
// Where start if the index of the first of thread and max is the maximum number of thread retrieved

所以当你这样做时： GmailApp.getInboxThreads（K，最大）[k]的;

您将范围K的 ONE 元素K检索到最大

获取所有帖子：

var threads = GmailApp.getInboxThreads();
//OR
var threads = GmailApp.getInboxThreads(k, max);
//Where K is starting email and max maximum number of thread

您的循环必须从零开始，因为您正在使用上下文GmailApp中的数组。所以：

var threads = GmailApp.getInboxThreads(k, max);
//threads is an array of threads range from 0 to max?
//Don't use k again!
for(var i=0; i<threads.length;i++){
 var currentThread = threads[i];
 //do what you need with the thread
}

为什么循环不将变量作为值：

2 个答案: