Question

在我的Android应用程序中，我需要测试编辑片段，能够从Android联系人中选择联系人。

我的问题是：是否有方法在Android espresso测试之前创建联系人并且在清单中没有WRITE_CONTACTS权限？或者我可以以某种方式模拟内容解析器吗？

以下是我如何联系的代码：

@OnClick(R.id.et_contact)
void chooseContactClick(View v) {
    launchContactPicker(v);
}

public void launchContactPicker(View view) {
    Intent contactPickerIntent = new Intent(Intent.ACTION_PICK,  ContactsContract.Contacts.CONTENT_URI);
    startActivityForResult(contactPickerIntent, CONTACT_PICKER_RESULT);
}

private ContactInf fetchPersonFromIntent(Intent data) {
    ContactInf contactInf = null;
    Uri uri = data.getData();
    ContentResolver cr = getActivity().getContentResolver();
    Cursor contentCursor = cr.query(uri, null, null,null, null);
    if(contentCursor.moveToFirst()) {
        String id = contentCursor.getString(contentCursor.getColumnIndexOrThrow(ContactsContract.Contacts._ID));

        // Perform a query to retrieve the contact's name parts
        String[] nameProjection = new String[] {
                ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME,
                ContactsContract.CommonDataKinds.StructuredName.MIDDLE_NAME,
                ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME
        };
        Cursor nameCursor = cr.query(
                ContactsContract.Data.CONTENT_URI,
                nameProjection,
                ContactsContract.CommonDataKinds.StructuredName.CONTACT_ID
                        + "=?", new String[]{id}, null);

        // Retrieve the name parts
        String firstName = StringUtils.EMPTY, middleName = StringUtils.EMPTY, lastName = StringUtils.EMPTY;
        if(nameCursor.moveToNext()) {
            firstName = nameCursor.getString(nameCursor.getColumnIndex(
                    ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME));
            middleName = nameCursor.getString(nameCursor.getColumnIndex(
                    ContactsContract.CommonDataKinds.StructuredName.MIDDLE_NAME));
            lastName = nameCursor.getString(nameCursor.getColumnIndex(
                    ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME));
            String msg = String.format(" contact %s %s %s %s ", id, firstName, middleName, lastName);
            Toast.makeText(getActivity(), msg, Toast.LENGTH_LONG).show();
            try {
                long idLong = Long.valueOf(id);
                contactInf = new ContactInf(idLong, firstName, middleName, lastName);
            } catch (NumberFormatException e) {
                Log.e(TAG, String.format(" NumberFormatException during parse id [%s] ", id));
            }
        }
    }
    return contactInf;
}

谢谢！

Answer 1

我通过在src \ debug \文件夹中添加一个清单文件解决了我的问题：uses-permission android：name =“android.permission.WRITE_CONTACTS”

在这种情况下，我有调试的WRITE_CONTACTS权限，没有按预期发布它。

在espresso测试之前创建联系

1 个答案: