Question

一直运行良好的php / mySQL预订功能突然停止将预订条目插入数据库，而不会更改代码和正常运行的数据库连接。

我运行在其他网站上工作的页面的并行版本;两者之间的唯一区别是破坏的版本在php 5.6上运行，运行的版本仍在5.4。

添加错误日志不会产生任何结果，即使表没有更新，我也看不到php 5.4和5.6之间的任何弃用语句。

有人能发现我失踪的问题吗？

 //If the confirm button has been hit:
if (isset($_POST['submit'])) {

//Create the foreach loop
  foreach ($_POST['class_id'] as $classes) {
  $class_id = (int)$classes;
  //UPDATE the bookings table **THIS PART IS NOT WORKING**:
  $query = "INSERT INTO bookings (user_id, booking_name, class_id, time_stamp) VALUES ('$user_id', '$username', '$class_id', NOW())";
  mysqli_query($dbc, $query);

}
foreach($_POST['class_id'] as $classes){
  $class_id = (int)$classes;
  //Change the booking numbers **THIS WORKS FINE**:
  $increase = "UPDATE classes SET online_bookings = (online_bookings + 1), total_bookings = (total_bookings + 1), free_spaces = (free_spaces - 1) WHERE class_id = $class_id";
  mysqli_query($dbc, $increase);
  }
   mysqli_close($dbc);

..以及提供$ _POST数据的表：

echo'<div class="container">';
echo'<div class="span8 offset1 well">';
echo'<p class="lead text-info">Do you want to reserve space at these classes?</p>';



//table header
echo '<table id="dancers" class="table table-bordered table-hover">';
  echo '<thead><tr><th>Date</th><th>Time</th><th>Venue</th><th>Who\'s going?</th></tr></thead>';
//create the form
echo '<form id="makebkg" method="post" action="' . $_SERVER['PHP_SELF'] . '">';


//Get the class IDs from the GET to use in the POST

    foreach ($_GET['sesh'] as $class_id) {

    $sql = "SELECT class_id, DATE_FORMAT(date, '%a, %d %b') AS new_date, DATE_FORMAT(time, '%H:%i') AS new_time, venue FROM classes WHERE class_id = '$class_id'";
    $data = mysqli_query($dbc, $sql);


//get table data
    while ($row = mysqli_fetch_array($data)) {
    $date = $row["new_date"];
    $time = $row["new_time"];
    $venue = $row["venue"];
    $class_id = $row["class_id"];
  }


//Show a table of the selected classes


      echo '<tr><td>' . $date . '</td>';
      echo '<td>' . $time . '</td>';
      echo '<td>' . $venue . '</td>';
      echo '<td>' . $username . '</td></tr>';
      echo '<input type="hidden" name="date[]" value="' . $date . '" />';
      echo '<input type="hidden" name="time[]" value="' . $time . '" />';
      echo '<input type="hidden" name="venue[]" value="' . $venue. '" />';
      echo '<input type="hidden" name="username[]" value="' . $username . '" />';
      echo '<input type="hidden" name="class_id[]" value="' . $class_id . '" />';



    }
 echo'</table>';



    //Go Back button
    echo '<a class="btn btn-link pull-left" href="classes.php"><i class="icon-arrow-left"></i> Go back</a>';

  // Make booking button - LIVE
      echo'<div id="confirmbtn">';
     echo '<input type="submit" id="confirm" name="submit" class="btn btn-large btn-primary pull-right" value="Confirm">';
      echo '</div>';

Answer 1

好的，我终于解决了这个问题。事实证明，托管公司已将MySQL模式更改为“严格”。

这里的INSERT语句将一些表列留空，严格模式拒绝整个插入结果。在插入命令之前更改模式比解决插入命令更快速地解决问题：

  // TURN OFF STRICT MYSQL MODE
  $strict = "SET sql_mode = ''";
  mysqli_query($dbc, $strict);

感谢惰性编码人员的所有建议和宽容。

Answer 2

您是否尝试检查查询？

error_reporting(1);

$q = mysqli_query($dbc, $query);

if (!$q)
{
  echo 'Error' . mysqli_error($dbc);
}

对其他查询也一样。

为什么MySQL INSERT语句无法正常工作

2 个答案: