Mysql - 为每个用户选择最后一行

时间:2017-03-05 12:19:55

标签: mysql message

这是我的疑问:

 SELECT msgId as `ID`,msgFromUserId , msgToUserId ,  
            DATE_FORMAT( msgDate,'%d/%m/%y %H:%i') as `time` ,  MID(msgText,1,30) as `text` , 
            (CASE WHEN (msgFromUserId=292646) then  b.user_login else  a.user_login END) as `sender`
            FROM tbl_messages inner join wp_users as a on tbl_messages.msgFromUserId=a.ID 
            inner join wp_users as b on tbl_messages.msgToUserId=b.ID 
            inner join tbl_forum_users u1 on tbl_messages.msgFromUserId=u1.user_ID 
            inner join tbl_forum_users u2 on tbl_messages.msgToUserId=u2.user_ID 
where (msgFromUserId=292646 or msgToUserId=292646)
and tbl_messages.msgId in (SELECT max(msgId) FROM tbl_messages   GROUP BY msgFromUserId, msgToUserId )
order by msgId desc

我明白了:

result table

我不想复制行。只是得到他们之间的最后一行对话

1 个答案:

答案 0 :(得分:2)

快速修复可能是更改子查询

SELECT max(msgId) FROM tbl_messages   GROUP BY msgFromUserId, msgToUserId

SELECT max(msgId) 
FROM tbl_messages
GROUP BY LEAST(msgFromUserId, msgToUserId), GREATEST(msgFromUserId, msgToUserId)

这会将消息从292646分组到1以及从1到292646。

完整查询:

SELECT msgId as `ID`,msgFromUserId , msgToUserId ,  
            DATE_FORMAT( msgDate,'%d/%m/%y %H:%i') as `time` ,  MID(msgText,1,30) as `text` , 
            (CASE WHEN (msgFromUserId=292646) then  b.user_login else  a.user_login END) as `sender`
            FROM tbl_messages inner join wp_users as a on tbl_messages.msgFromUserId=a.ID 
            inner join wp_users as b on tbl_messages.msgToUserId=b.ID 
            inner join tbl_forum_users u1 on tbl_messages.msgFromUserId=u1.user_ID 
            inner join tbl_forum_users u2 on tbl_messages.msgToUserId=u2.user_ID 
where (msgFromUserId=292646 or msgToUserId=292646)
and tbl_messages.msgId in (
    SELECT max(msgId) 
    FROM tbl_messages
    GROUP BY LEAST(msgFromUserId, msgToUserId), GREATEST(msgFromUserId, msgToUserId)
)
order by msgId desc

要提高性能,还应将user-id-condition移动到子查询中:

SELECT max(msgId) 
FROM tbl_messages
where (msgFromUserId=292646 or msgToUserId=292646) -- <-- here
GROUP BY LEAST(msgFromUserId, msgToUserId), GREATEST(msgFromUserId, msgToUserId)

要使用索引,最好使用UNION ALL优化方法。但这看起来很复杂:

SELECT max(msgId)
FROM (
    SELECT msgToUserId as otherUserId, max(msgId) as msgId
    FROM tbl_messages 
    WHERE msgFromUserId=292646 
    GROUP BY msgToUserId

    UNION ALL

    SELECT msgFromUserId as otherUserId, max(msgId) as msgId
    FROM tbl_messages 
    WHERE msgToUserId=292646 
    GROUP BY msgFromUserId
) sub
GROUP BY otherUserId

请注意,这只是在WHERE子句中使用的子查询(tbl_messages.msgId in (...))。

此子查询也可以用作派生表,因此我们可以将其与tbl_messages一起加入:

SELECT msgId as `ID`,
       msgFromUserId,
       msgToUserId,  
       DATE_FORMAT( msgDate,'%d/%m/%y %H:%i') as `time`,
       MID(msgText,1,30) as `text` , 
       (CASE WHEN (msgFromUserId=292646) then  b.user_login else  a.user_login END) as `sender`
FROM (
    SELECT max(msgId) as msgId
    FROM (
        SELECT msgToUserId as otherUserId, max(msgId) as msgId
        FROM tbl_messages 
        WHERE msgFromUserId=292646 
        GROUP BY msgToUserId
        UNION ALL
        SELECT msgFromUserId as otherUserId, max(msgId) as msgId
        FROM tbl_messages 
        WHERE msgToUserId=292646 
        GROUP BY msgFromUserId
    ) sub
    GROUP BY otherUserId
) sub
inner join tbl_messages on tbl_messages.msgId = sub.msgId
inner join wp_users as a on tbl_messages.msgFromUserId=a.ID 
inner join wp_users as b on tbl_messages.msgToUserId=b.ID 
inner join tbl_forum_users u1 on tbl_messages.msgFromUserId=u1.user_ID 
inner join tbl_forum_users u2 on tbl_messages.msgToUserId=u2.user_ID 
order by tbl_messages.msgId desc

您需要以下索引来支持子查询:

tbl_messages(msgFromUserId, msgToUserId [, msgId])
tbl_messages(msgToUserId, msgFromUserId [, msgId])