Question

我想了解为什么在我冻结模拟类而不是模拟界面时我的测试失败

[Fact]
public void MethodeName()
{
    var fixture = new Fixture().Customize(new AutoMoqCustomization());

    var webRequestMock = fixture.Freeze<Mock<MyWebRequest>>(); // freezing a class + setuping a return value
    webRequestMock.Setup(a => a.GetData())
    .Returns("Foo");

    var myService = fixture.Create<MyService>();

    var actual = myService.GetData();

    webRequestMock.Verify(a => a.GetData(), Times.Once()); // Failed it's never called once
    Assert.Equal("Foo", actual); // Failed, if we comment previous line, 'actual' value is always empty
}

public class MyService
{
    private readonly MyWebRequest _request;

    public MyService(MyWebRequest request)
    {
        _request = request;
    }

    public string GetData()
    {
        var data = _request.GetData();
        return data;
    }
}

public class MyWebRequest 
{
    public virtual string GetData() // you can see here, the method is well virtual, and should be overridable by moq.
    {
        return string.Empty;
    }
}

1 / 如果我尝试使用模拟界面，则可以正常工作。

[Fact]
public void MethodeName()
{
    var fixture = new Fixture().Customize(new AutoMoqCustomization());
    const string expected = "Foo";

    var webRequestMock = fixture.Freeze<Mock<IMyWebRequest>>();
    webRequestMock.Setup(a => a.GetData())
    .Returns("Foo");

    var myService = fixture.Create<MyService>();

    var actual = myService.GetData();

    webRequestMock.Verify(a => a.GetData(), Times.Once()); // Success
    Assert.Equal(expected, actual); // Success
}

public class MyService
{
    private readonly IMyWebRequest _request;

    public MyService(IMyWebRequest request)
    {
        _request = request;
    }

    public string GetData()
    {
        var data = _request.GetData();
        return data;
    }
}

public interface IMyWebRequest
{
    string GetData();
}

public class MyWebRequest : IMyWebRequest
{
    public virtual string GetData()
    {
        return string.Empty;
    }
}

2 / 如果我使用＆＃39;注入＆＃39;而不是冻结，它的工作原理：

[Fact]
public void MethodeName()
{
    var fixture = new Fixture().Customize(new AutoMoqCustomization());
    const string expected = "Foo";

    var webRequestMock = new Mock<MyWebRequest>(); 
    webRequestMock.Setup(a => a.GetData()).Returns("Foo");
    fixture.Inject(webRequestMock.Object);

    var myService = fixture.Create<MyService>();

    var actual = myService.GetData();

    webRequestMock.Verify(a => a.GetData(), Times.Once()); // Success
    Assert.Equal(expected, actual); // Success
}

public class MyService
{
    private readonly MyWebRequest _request;

    public MyService(MyWebRequest request)
    {
        _request = request;
    }

    public string GetData()
    {
        var data = _request.GetData();
        return data;
    }
}

public class MyWebRequest 
{
    public virtual string GetData()
    {
        // make WebRequest
        return string.Empty;
    }
}

我的自动混合版本：3.6.5.0

Answer 1

MyWebRequest是一个具体的（非抽象）类， AutoFixture.AutoMoq 不会使用 Moq 创建它们。这是按设计，因为 AutoFixture 内核已经处理了＆＃39; normal＆＃39;类。

You can change this behaviour如果您愿意的话。但是，我经常考虑不得不这样做一个设计气味。但是，在这种情况下很难说，因为你已经很好地将问题减少到最小的重复。但问题是，如此处所示，MyService不会添加任何值。我确定这不是你的真实代码的样子，但由于我无法猜出你的真实代码是什么样子，我无法判断一个更好的设计是否可行。

AutoFixture + Moq - 冻结模拟类可防止设置

1 个答案: