Question

在PHP中，我想更改此字符串：

",,,3,4,,,5,6,,7,8,"

进入这个：

"3,4,5,6,7,8"

我设法在字符串的开头和结尾处删除逗号，但这只能满足我50％的需求：

<?php
$hello = ",,,3,4,5,6,,7,8,";
echo rtrim(ltrim($hello,","),",");

结果：

"3,4,,,5,6,,7,8"

任何解决方案？

Answer 1

这个小技巧：

$hello = ",,,3,4,,,5,6,,7,8,";
$hello = implode(",",array_filter(explode(',',$hello)));

如果你的字符串更复杂（即它是一个CSV，可能有字段包含在＆＃34;＆＃34;以逃脱逗号，你可以这样做：

$hello = ",,,3,4,,,5,6,,\"I,have,commas\",,7,8,";
$fields = array_filter(str_getcsv($hello));
$hello = str_putcsv($fields);

https://gist.github.com/johanmeiring/2894568中将str_putcsv定义为

if (!function_exists('str_putcsv')) {
    function str_putcsv($input, $delimiter = ',', $enclosure = '"') {
        $fp = fopen('php://temp', 'r+b');
        fputcsv($fp, $input, $delimiter, $enclosure);
        rewind($fp);
        $data = rtrim(stream_get_contents($fp), "\n");
        fclose($fp);
        return $data;
    }
}

Answer 2

您可以使用trim（）和Regx实现此目的，请查看以下代码，它可能对您有所帮助

$from = ",,,,,,3,4,,,5,6,,7,8,,,";
echo $from;
echo "<pre>";
$to = preg_replace('/,+/', ',', trim($from,","));
echo $to;

Answer 3

implode(",", array_filter(explode(",", ",,,3,4,,,5,6,,7,8,"))

这是一点点阅读，但基本上是explode逗号上的字符串，在结果上调用array_filter，然后implode将它重新组合在一起。

PHP在字符串中截断逗号

3 个答案: