Question

我有一个包含字典的数组。在每个字典中再次包含字典数组。我想弄清楚所有具有特定价值的物体，比如印度。我试过NSpredicate。示例字典数组

{
 Destination : [
                {
                    plan : [
                            {
                               name : "India"
                             },
                             {
                               name : "India"
                             }
                           ]
                       },
                {
                    plan : [
                            {
                               name : "Germany"
                             },
                             {
                               name : "Germany"
                             }
                           ]
                       }
                    ]
                 }

对于这本词典，我的代码是

NSMutableArray * destinationArray = [[NSMutableArray alloc]init];
            [destinationArray addObject:[ResponseObject objectForKey:@"Destination"]];
            NSPredicate * predicate = [NSPredicate predicateWithFormat:@"name CONTAINS[cd] %@",@"India"];
            NSArray * filtered = [destinationArray filteredArrayUsingPredicate:predicate];

Answer 1

NSMutableArray* container = [NSMutableArray new];
for (NSMutableDictionary* d in firstArray) {
    for (NSMutableDictionary* d2 in d[@"plan"]) {
        [container addObject: [d2[@"name"] mutableCopy];
    }

}

我相信这会做到这一点

Answer 2

NSPredicate * predicate = [NSPredicate predicateWithFormat:@"name CONTAINS[cd] %@",[[[ResponseObject objectAtIndex:i]objectForKey:@"destination"]objectForKey:@"name"]];

在您的代码中，当在此处致电[[ResponseObject objectAtIndex:i]objectForKey:@"destination"]时，NSArray包含一些NSDictionary。当你拨打objectForKey:@"name"时，它会向你发送错误，你确定你的代码是最新的吗？

这是我的测试跟随你的数据结构，结果是最新的。

    NSArray *array = @[@{@"name" : @"zhangsan",
                     @"age" : @"10",
                     @"result": @[
                                  @{@"res":@"123l"},
                                  @{@"res":@"789l"}
                                ]
                    },
                   @{@"name" : @"lisi",
                     @"age" : @"11",
                     @"result": @[
                                  @{@"res":@"123l"},
                                  @{@"res":@"789l"}
                                ]
                    },
                   @{@"name" : @"wangwu",
                     @"age" : @"12",
                     @"result": @[
                                  @{@"res":@"123l"},
                                  @{@"res":@"789l"}
                                ]
                    }];

NSString *preStr = @"res";
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"%K CONTAINS[c] %@",preStr, @"123"];
NSMutableArray *result = [NSMutableArray array];
for (NSDictionary *dict in array) {
    NSArray *res = dict[@"result"];
    [result addObjectsFromArray:[res filteredArrayUsingPredicate:predicate]];
}
NSLog(@"final result == %@",result);

从Dictionary数组中找出一个特定的值

2 个答案: