我已经创建了两个表，我正在尝试合并它们但是由于某种原因它不起作用。
我的两张表是：
table_account_id = data1.groupby('employer_key').account_id.nunique() #how many people logged in (unique account id)
table_eligible = data3.groupby(['employer_key'])[['eligible']].sum().astype('int') #eligible population
我希望我的新表格包含以下列：
Employer_key // account_id // eligible
我认为代码如下，但它不起作用：
new_table = pd.merge(table_eligible, table_account_id, left_index=True, right_index=True)
我能够合并这两个表，直到我将nunique函数插入到table_account_id代码中。
谢谢！
答案 0 :(得分：0)
我在手机上，你没有发布数据。穿过我的手指，这是有效的。
Layer (type) Output Shape Param # Connected to
====================================================================================================
input_1 (InputLayer) (None, 3, 225, 225) 0
____________________________________________________________________________________________________
maxpooling2d_1 (MaxPooling2D) (None, 3, 113, 113) 0 input_1[0][0]
____________________________________________________________________________________________________
convolution2d_1 (Convolution2D) (None, 32, 113, 113) 128 maxpooling2d_1[0][0]
____________________________________________________________________________________________________
convolution2d_2 (Convolution2D) (None, 32, 113, 113) 1056 convolution2d_1[0][0]
____________________________________________________________________________________________________
merge_1 (Merge) (None, 64, 113, 113) 0 convolution2d_2[0][0]
convolution2d_1[0][0]
____________________________________________________________________________________________________
merge_2 (Merge) (None, 96, 113, 113) 0 convolution2d_1[0][0]
merge_1[0][0]
____________________________________________________________________________________________________
merge_4 (Merge) (None, 128, 113, 113) 0 merge_2[0][0]
convolution2d_2[0][0]
____________________________________________________________________________________________________
flatten_1 (Flatten) (None, 1634432) 0 merge_4[0][0]
____________________________________________________________________________________________________
activation_1 (Activation) (None, 1634432) 0 flatten_1[0][0]
====================================================================================================