编译此代码时出错。 Z
是进行更改所需的硬币的最终计数,目的是使用最少数量的硬币。我在顶部附近定义了int Z = 0
。我已尝试再次添加int z
并在打印语句中将类型更改为f
,但没有运气。
这是错误:
error: format specifies type 'int' but the argument has type '<dependent type>' [-Werror,-Wformat]
greedy.c:77:16: error: use of undeclared identifier 'z'
printf("%i\n", z);
这是我的代码。我是初学者,所以欢迎任何建议或更正。
#include <stdio.h>
#include <cs50.h>
#include <math.h>
int main(void)
{
//prompt user for amount of change owed
float f;
int num; //amount of change
do
{
printf("O hai! How much change is owed?:\n");
f = get_float();
}
while (f < 0); //verify input is positive
num = round(f * 100); //rounds float
//commence making change
do{
int c, e, i, j;
int z = 0; //z = coins
if (num % 25 == 0) // verifies that num is divisible by 25 so only 25c coins necessary
{
z = (num/25) + z; // updates final number of 25c coins
}
else if (num % 25 > 0)
{
i = num / 25;
j = num % 25;
}
else if ((num / 25 < 0) || (num >=10 && num < 25)) //this means that f is less than 25 cents so has to be divided by 10 cent coins
{
num = c;
c = j + c; //add remainder of num to the number to start with
}
if (c % 10 == 0) // c is less than 25c but divisible by 10c pieces
{
z = (c / 10) + z; //d is the final number of 10c coins
}
else if (c /10 < 1) //this means it's less than 10c
{
c = e; // Then c must be less than 10c
}
else if (e % 5 == 0) // divisible by 5c pieces
{
z = (e / 5) + z; // g is the number of 5 cent pieces
}
else if (e % 5 < 0)
{
z = (e / 1) + z; //h is the number of pennies
}
}
while (num > 0); //num is rounded float
printf("%i\n", z);
}
答案 0 :(得分:1)
首先,我建议您应该使用缩进来正确格式化代码。
然后,错误的原因是z
在与do
循环相关联的块内声明,printf("%i\n", z);
超出其范围。
要摆脱此错误,请在z
调用可见的位置声明printf()
- 例如,在do
循环之前。
请注意,声明int Z = 0
无法正常工作,因为标识符&#39;名称在C中区分大小写。
答案 1 :(得分:0)
就像已经说过的那样,你在do-while循环中声明了z,所以它只在循环内部可见。
你应该在循环开始之前声明它,所以你也可以在循环结束后使用它。像这样:
int z = 0; //z = coins
do{
***YOUR CODE***
} while();