Question

我目前的json看起来像这样：

int total = 0;
String word_search = Etxt.getText().toString().trim().toLowerCase();
String fullTxt = textView.getText().toString();
String[] array = fullTxt.split("\n");
String[] markiert = new String[array.length]
String word;
StringBuilder st = new StringBuilder();
for (int i = 0; i < array.length; i++) {
    word = array[i];
    if (word.toLowerCase().contains(word_search)) {
        markiert[i] = word.trim();//this is result in array do whatever you want with it
        st.append("<b><i>" + markiert[i] + "</i></b>");
        total++;
    } else {
        st.append(word);
    }
    st.append("<br>");
}
textView.setText(Html.fromHtml("" + st));
text_total.setText("Ergebnisse: " + total);

我也在vb中将其分解为：

{
  "Ebay": {
    "international": {
      "singles": 308,
      "bundle batches": 87,
      "multiples": 30,
      "mixed multis": 47
    },
    "first class": {
      "mixed multis": 9,
      "singles": 94,
      "multiples": 12,
      "bundle batches": 13
    },
    "singles": {
      "all": 1246
    },
    "multiples": {
      "all": 84
    },
    "over 15.5": {
      "multiples": 40,
      "singles": 9,
      "mixed multis": 62,
      "bundle batches": 8
    },
    "bundle batches": {
      "all": 135
    },
    "mixed multis": {
      "all": 66
    },
    "priority": {
      "singles": 16,
      "bundle batches": 5,
      "mixed multis": 3,
      "multiples": 2
    },
    "high value": {
      "multiples": 1,
      "bundle batches": 19,
      "singles": 3
    },
    "apo/fpo": {
      "singles": 1
    }
  }
}

将它分开很好，但我想知道的是我怎么能看到“混合多重”是否出现在“高价值”分支下，如果它不添加它，但如果它没有添加，则添加到它的现有价值

我已经创建了这个有助于最低级别..但不知道如何在字典中的字典中引用字典

    Dim data As Dictionary(Of String, Dictionary(Of String, Dictionary(Of String, Integer))) = JsonConvert.DeserializeObject(Of Dictionary(Of String, Dictionary(Of String, Dictionary(Of String, Integer))))(mystring)

我会把它创建为一个类或结构，但不确定当键不总是标准时如何做到这一点..即“国际”，“apo / fpo”它们并不总是存在，

提前谢谢

Answer 1

尝试使用.ContainsKey，如果它不包含密钥，则可以为每个级别的数据创建字典。

如何在词典词典中添加“子词典”？

1 个答案: