Question

我想通过简单的脚本从数据库中获取数据

<a href='category.php?CAT=Shoes'>Shoes</a>

然后简单地在“CAT”列中显示具有特定数据的所有行，如下所示：

$CAT = $_GET['CAT'];
    $sql = "SELECT * FROM Shop WHERE CAT = $CAT" ;
       $result = $conn->query($sql);
if ($result->num_rows > 0) {
    while($row = $result->fetch_assoc()) { 
echo"
... results
"}}

问题是这个脚本适用于INT（例如SELECT CAT = 5，类似于category.php？CAT = 5）但不适用于VARCHAR（SELECT CAT =类似category.php？CAT = Shoes）。现在我不确定为什么会这样。出错：试图获取非对象的属性

Answer 1

$sql = "SELECT * FROM Shop WHERE CAT = '$CAT'"

Answer 2

您需要将$cat作为字符串

传递

$cat = $_GET['CAT'];

$sql = "SELECT * FROM Shop WHERE CAT = '{$cat}'" ;

$result = $conn->query($sql);

if ($result->num_rows > 0) {
    while($row = $result->fetch_assoc()) { 
        echo '<pre>' . print_r($row, true) . '</pre><br/>';
    }
}

从MySql DB中的URL获取数据

2 个答案: