Question

我正在尝试从表中删除行。表名是用户的username（用户登录）

删除页面在这里

require('db.php');
if(isset($_POST["deletebtn"])){
   $x = $_SESSION['username'];
   $id=$_POST["statusid"];
   $row=$conn->query("select id from $x where id='$id'");
   if ($conn->query($row) === TRUE) {
      $sql = "delete from $x where id ='$id'";
      //  echo 'success';
      header( "Refresh:3; url=admin2.php", true, 303);
   }else{
      echo "not";
   }
 }

这是我的内容代码

$sql = "SELECT id,date,status FROM $x order by id DESC;";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
   while($row = $result->fetch_assoc()) {
      $id = $row['id'];
      echo "<div class='border'> ";
      echo "";
      echo "<form action='deletepage.php?action=$id'>";
      echo "<input type='hidden' name='statusid' value='$id' >";
      echo  "<p> " . $row["status"] ."</p><br>";
      echo "<input type='submit' value='delete' class='btn1 pull-right' name='deletebtn'> ";
      echo "<a class=' btn1 pull-right' href='#'>edit &nbsp;&nbsp;</a>";
      echo  "<small> " . $row["date"]. "</small><br>";
      echo "</form>";
      echo "</div>";            
    } 
} else {............}

Answer 1

您没有在sql上执行查询

$sql = "delete from $x where id ='$id'";

像

一样执行

$del= $conn->query($sql);

查询后

Answer 2

您忘记执行查询

require'db.php';
if(isset($_POST["deletebtn"])){
$x = $_SESSION['username'];
$id=$_POST["statusid"];
 $row="select id from $x where id='$id'"; //<---remove query execution from here
 if ($conn->query($row) === TRUE) {
   $sql = "delete from $x where id ='$id'";
    $conn->query($sql); //<-------- Add this line
 //  echo 'success';
   header( "Refresh:3; url=admin2.php", true, 303);
  }else{
 echo "not";
 }
 }

Answer 3

您的代码存在一些问题。

删除查询没有执行查询。（稍后可能会解决）
在你的while循环中放入$ conn-＆gt;查询（$ row）这是错误的。 $ row不是查询...它是从先前查询返回的结果集。
最后$ conn-＆gt;查询在SELECT，SHOW，DESCRIBE或EXPLAIN查询中不返回true。 Check php manual

Answer 4

改变这个 $sql = "delete from $x where id ='$id 为$sql = "delete from $table where id ='$sessionid'

无法使用sql删除表中的数据

4 个答案: