我为这个作业制作了这个数组,但我不能完全正确。我需要它做的是识别我的数组中的字符串并打印出“我正在学习它”。我想我很接近,但我一直在接受未定义的偏移。
$myArray = array ("C ", "Java", "C++ ", "Objective-C", "C#", "PHP","(Visual)
Basic", "Python", "JavaScript", "Perl", "Ruby",
"PL/SQL", "Delphi/Oject pascal","Visual Basic.Net",
"lisp", "Pascal", "Ada", "Transact-SQL", "Logo", "NXT-G");
for ($i = 0; $i<sizeof($myArray); $i++)
echo $myArray[$i];
if($myArray[$i] == "C") {
echo "I'm learning this too!";
}
else {
echo "Your not learning anything";
}
答案 0 :(得分:2)
您缺少for loop
$myArray = array ("C ", "Java", "C++ ", "Objective-C", "C#", "PHP","(Visual)
Basic", "Python", "JavaScript", "Perl", "Ruby",
"PL/SQL", "Delphi/Oject pascal","Visual Basic.Net",
"lisp", "Pasca", "Ada", "Transact-SQL", "Logo", "NXT-G");
for ($i = 0; $i< sizeof($myArray); $i++)
{
echo $myArray[$i]."<br>";
if($myArray[$i] == "C") {
echo "I'm learning this too!";
}
else {
echo "Your not learning anything";
}
}
答案 1 :(得分:1)
您在for循环中缺少括号括起来。
for循环多次执行for命令后的单个指令。如果你想做多件事,你需要将它们组合成一个带括号{}
的块for ($i = 0; $i<sizeof($myArray); $i++)
{
echo $myArray[$i];
if($myArray[$i] == "C")
{
echo "I'm learning this too!";
}
else
{
echo "Your not learning anything";
}
}
尝试并严格遵守您的积木的布局格式,否则当您的大括号没有正确链接时,您会更难注意到。