Question

我想检查XML中的重复元素。请帮忙！

XML：

<?xml version="1.0" encoding="utf-8"?>
<List>
  <Email_Entry></Email_Entry>
  <Email_Entry EmailID="qw@gmail.com" />
  <Email_Entry EmailID="qw@gmail.com" />
  <Email_Entry EmailID="qw@gmail.com" />
  <Email_Entry EmailID="qw@gmail.com" />
  <Email_Entry EmailID="shssh@gmail.com" />
</List>

aspx.cs：

protected void btnEmailSubscribe_Click(object sender, EventArgs e)
{            
    string EmailID = txtEmailSubscribe.Text;
    string FILE_PATH = Server.MapPath("~/Logs/SubscribedEmails.xml");

    XDocument Emailxml = XDocument.Load(FILE_PATH);
    var EmailExist = Emailxml.Descendants("Email_Entry")
        .Any(x => (string)x.Element("EmailID") == txtEmailSubscribe.Text);
    if (EmailExist)
    {
        lblEmail.Text = "EmailID already exist";
    }
    else
    {
        Emailxml.Root.Add(new XElement("Email_Entry",
                   new XAttribute("EmailID", EmailID)
               ));
        Emailxml.Save(FILE_PATH);
        lblEmail.Text = "Subscribed Successfully";
    }            
}

Answer 1

检查属性值而不是元素：

var EmailExist = Emailxml.Descendants("Email_Entry")
        .Any(x => x.Attribute("EmailID").Value == txtEmailSubscribe.Text);

Answer 2

var xml = File.ReadAllText（＆＃34;您的xml文件路径＆＃34;）;

public void processStartNotification() {
    final NotificationCompat.Builder builder = new NotificationCompat.Builder(locationActivity);
    builder.setContentTitle("New Item Received")
            .setAutoCancel(true)
            .setContentText(title)//coming from server
            .setSmallIcon(R.drawable.app_logo);

    Intent mainIntent = new Intent(context,Activity.class);
    PendingIntent pendingIntent = PendingIntent.getActivity(context,
            NOTIFICATION_ID,
            mainIntent,
            PendingIntent.FLAG_UPDATE_CURRENT);
    builder.setContentIntent(pendingIntent);
    PreferenceClass.setBooleanPreference(locationActivity,Constant.NOTIFICATION,true);
    final NotificationManager manager = (NotificationManager) this.locationActivity.getSystemService(Context.NOTIFICATION_SERVICE);
    manager.notify(NOTIFICATION_ID, builder.build());
}

C＃：检查XML中的重复元素

2 个答案: