Question

我正在使用saxon和xslt执行从一种xml格式到另一种xml格式的xslt转换，之后将结果xml转换为Java DOM以进一步处理它：

System.setProperty("javax.xml.transform.TransformerFactory", "net.sf.saxon.TransformerFactoryImpl");
TransformerFactory tFactory = TransformerFactory.newInstance();

Transformer transformer = tFactory.newTransformer(new StreamSource(new File("xslt.xsl")));
transformer.transform(new StreamSource(new File(inputXML)),
                                  new StreamResult(new File (outputXML)));

DocumentBuilder documentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document document = documentBuilder.parse(outputXML);

在这种情况下我不喜欢创建中间outputXML文件。有可能避免它的产生吗？

Answer 1

DocumentResult result = new DocumentResult（）;

transformer.transform（new StreamSource（new File（inputXML）），result）;

Document transformedDoc = result.getDocument（）;

Answer 2

答案由@Andreas提供。如果有人感兴趣，我案例中的结果代码段看起来像这样：

System.setProperty("javax.xml.transform.TransformerFactory", "net.sf.saxon.TransformerFactoryImpl");
TransformerFactory tFactory = TransformerFactory.newInstance();

DOMResult xmlResult = new DOMResult();
Transformer transformer = tFactory.newTransformer(new StreamSource(new File("xslt.xsl")));
        transformer.transform(new StreamSource(new File(outputXML)),
                              xmlResult);

Document document = (Document) xmlResult.getNode();

Java：将StreamResult转换为DOM

2 个答案: