Question

我使用gtk.Menu()创建了一个gtkMenu，附加了几个项目，现在我想删除一些菜单项。我怎么能这样做？

Answer 1

这应该可以解决问题：

for i in menu.get_children():
    menu.remove(i) # check here if you want to remove this child

gtk.Menu继承自gtk.Container

http://www.pygtk.org/docs/pygtk/class-gtkcontainer.html

编辑

# First remove all old timer menu items from the gtkMenu
if TimerAppIndicator.menuList:
    for i in TimerAppIndicator.menuList:
        self.menu.remove(TimerAppIndicator.menuList[j])
        j+=1 <---- 1) j isn't declared here 
                   2) you will skip items why not just self.menu.remove(i)
                      you're already iterating over the menu items


# Delete all timer menu items from the list storing them
del TimerAppIndicator.menuList[:]
j=0  <--------- shouldn't this be before j+=1?

Answer 2

也许使用 destroy() 可以节省一些 RAM：

menu.foreach(lambda child: child.destroy())

如何从gtkMenu中删除项目？

2 个答案: