Question

我正在向我的应用添加通知，如果应用关闭，Everyting工作正常，它会按照我想要的方式触发通知，但是当我启动应用时，在创建时称为通知触发。如果我离开应用并再次启动应用，则会再次触发通知。

然而，当我打开我的应用程序通知时会发生火灾。我不希望这种行为。

这是用于通知的代码，我将代码放在onCreate中：我知道我应该从onCreate移动它，但移动它的位置？是否可以检查已经设置的警报，如果是，则不再发射通知。

AlarmManager manager = (AlarmManager) getSystemService(ALARM_SERVICE); 
Intent intent = new Intent(this, NotificationService.class);
PendingIntent pendingIntent = PendingIntent.getService(this, 100, intent, PendingIntent.FLAG_UPDATE_CURRENT);
manager.setInexactRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP, 1000 , 1000 * 60 * 45, pendingIntent);

＆＃13;

protected void onHandleIntent(Intent intent) {
        Log.d(TAG, "onHandleIntent: ");

       
        Realm realm = null;
        try{
            realm = Realm.getDefaultInstance();
            RealmResults<Drop> results = realm.where(Drop.class).equalTo("completed", false).equalTo("deleted", false).findAll();
            for(Drop current : results){
                if(isNotificationNeeded(current.getAdded(), current.getWhen(), current.isSwitchButtonchecked())){
                    fireNotification(current);
                }
            }
        } finally {
            if(realm!=null){
                realm.close();
            }
        }
    }

＆＃13;

public class NotificationService extends IntentService {
    public static final String TAG = "holaa";
    private long vrijemeStartAlarmUDevetSati = 1000*60*60*9; //milisecunds*secoonds*min*hours* - from 9h
    private long vrijemeAlarmDoJedanestSati = 1000*60*60*23;  //milisecunds*secoonds*min*hours* - to 23h
    Bundle bundle;
    int i = 0;


    public NotificationService() {
        super("NotificationService");
        Log.d(TAG, "NotificationService: ");
    }

    @Override
    protected void onHandleIntent(Intent intent) {
        Log.d(TAG, "onHandleIntent: ");

//realm database
        Realm realm = null;
        try{
            realm = Realm.getDefaultInstance();
            RealmResults<Drop> results = realm.where(Drop.class).equalTo("completed", false).equalTo("deleted", false).findAll();
            for(Drop current : results){
                if(isNotificationNeeded(current.getAdded(), current.getWhen(), current.isSwitchButtonchecked())){
                    fireNotification(current);
                }
            }
        } finally {
            if(realm!=null){
                realm.close();
            }
        }
    }

    private void fireNotification(Drop drop) {
        i = i+1;

        String messageTitle = drop.getWhat();
        String messageNote = drop.getWhat_note();
        int ikonicaBojaNota = drop.getColorPickerRoudIcon();
       



        PugNotification.with(this)
                .load()
                .identifier(i)
                .title(messageTitle)
                .message(messageNote)
                .bigTextStyle(messageNote)
                .smallIcon(R.drawable.ic_drop)
                .largeIcon(R.drawable.logo)
                .flags(Notification.DEFAULT_ALL)
                .autoCancel(true)
                .click(Main2Activity.class, bundle)
                .color(color)
                .simple()
                .build();
    }

    private boolean isNotificationNeeded(long added, long when, boolean switchButtonchecked){
        long now = System.currentTimeMillis();

        if ((now>when+ vrijemeStartAlarmUDevetSati) &&  (now < (when + vrijemeAlarmDoJedanestSati)) && switchButtonchecked == true){
            bundle = new Bundle();
            bundle.putLong("notification", added);
            return true;
        }
        else {
            //do nothing
            return false;
        }
    }
}

＆＃13;

Answer 1

启动服务与创建通知无关。您的活动应该只启动该服务。它不应该创建任何通知。服务启动后，它负责创建通知。

我打开应用时会启动Android通知

1 个答案: