我可以得到一些帮助。
查询如下:
SELECT
SUBSTR(house.nr,1,3), SUM(road.quantity),
COUNT(people.name), goods.price*sum(road.quantity) /goods.quantity
FROM home, road, house, goods, people
WHERE home.hoid = road.roid
AND home.hrid = house.nrid
AND road.gdsid = goods.goodsid
AND goods.nmid = people.nameid
GROUP BY SUBSTR(nr,1,3), people.name, goods.price, road.quantity, goods.quantity
ORDER BY SUBSTR(nr,1,3)
先谢谢。
答案 0 :(得分:0)
您按名称,价格和数量进行分组,因此每个值的结果将包含一行。而是通过第一列选择聚合和分组:
SELECT
SUBSTR(house.nr,1,3), SUM(road.quantity), COUNT(people.name),
SUM(goods.price*sum(road.quantity) /goods.quantity) AS price
...
GROUP BY SUBSTR(house.nr,1,3)