计算Oracle中的总和时间

时间:2017-03-03 13:36:54

标签: oracle time sum timestamp

我在Oracle中有这个表,电子邮件和时间都是varchar。

Email               Time
----------------    -----------
paolo@gmail.com     00:10:40
paolo@gmail.com     00:40:10
paolo@gmail.com     01:10:20
paolo@gmail.com     00:43:40
paolo@gmail.com     00:42:40
chiara@gmail.com    00:30:40
chiara@gmail.com    00:54:10
chiara@gmail.com    00:47:40
simo@gmail.com      00:50:40
simo@gmail.com      01:05:40
simo@gmail.com      00:45:40
simo@gmail.com      00:51:40
simo@gmail.com      00:36:40

我希望通过电子邮件获得时间和小组的总和。是否可以在Oracle中使用?

更新

时间是持续时间。

1 个答案:

答案 0 :(得分:4)

使用此查询

SQL> WITH table_(Email, Time) as (
  2      select 'paolo@gmail.com', '00:10:40' from dual union all
  3      select 'paolo@gmail.com', '00:40:10' from dual union all
  4      select 'paolo@gmail.com', '01:10:20' from dual union all
  5      select 'paolo@gmail.com', '00:43:40' from dual union all
  6      select 'paolo@gmail.com', '00:42:40' from dual union all
  7      select 'chiara@gmail.com', '00:30:40' from dual union all
  8      select 'chiara@gmail.com', '00:54:10' from dual union all
  9      select 'chiara@gmail.com', '00:47:40' from dual union all
 10      select 'simo@gmail.com', '00:50:40' from dual union all
 11      select 'simo@gmail.com', '01:05:40' from dual union all
 12      select 'simo@gmail.com', '00:45:40' from dual union all
 13      select 'simo@gmail.com', '00:51:40' from dual union all
 14      select 'simo@gmail.com', '00:36:40' from dual )
 15  ---------------------
 16  -- End if sample data
 17  ---------------------
 18  SELECT email, numtodsinterval(sum(SUBSTR(TIME, 1, 2)*3600 + SUBSTR(TIME, 4, 2)*60 + SUBSTR(TIME, 7, 2)), 'SECOND') total_duration
 19    FROM table_
 20   GROUP BY email;

输出:

EMAIL            TOTAL_DURATION
---------------- --------------------------------------------------------------------------------
chiara@gmail.com +000000000 02:12:30.000000000
simo@gmail.com   +000000000 04:10:20.000000000
paolo@gmail.com  +000000000 03:27:30.000000000

所以,你的查询是

SELECT email, numtodsinterval(sum(SUBSTR(TIME, 1, 2)*3600 + SUBSTR(TIME, 4, 2)*60 + SUBSTR(TIME, 7, 2)), 'SECOND') total_duration
  FROM table_
 GROUP BY email;