我有以下查询将数据插入多对多连接表
INSERT INTO playlist_genre(playlist_id, genre_id)
VALUES (${playlistId}, ${genre1Id}),
(${playlistId}, ${genre2Id}),
(${playlistId}, ${genre3Id})
);
然而,我遇到的问题是,用户不需要值genre2Id
和genre3Id
,因此可以是INTEGER
或NULL
我试图找到一种方法来编写同样的查询,但只有在存在值时才会插入。两列都有NOT NULL
个约束。
修改:
这是我的播放列表
class Playlist {
constructor(playlist) {
// required fields
this.title = playlist.title;
this.playlistType = playlist.playlistType;
this.userId = playlist.userId;
this.numberOfTracks = playlist.numberOfTracks;
this.lengthInSeconds = playlist.lengthInSeconds;
this.genre1Id = playlist.genre1Id;
// not required fields
this.genre2Id = playlist.genre2Id || null;
this.genre3Id = playlist.genre3Id || null;
this.description = playlist.description || null;
this.releaseDate = playlist.releaseDate || null;
}
save() {
return new Promise((resolve, reject) => {
db.one(sqlCreatePlaylist, this)
.then((insertedPlaylist) => {
// Here is where i want to use insertedPlaylist's id
// to insert data into 'playlist_genre' table
resolve(insertedPlaylist);
})
.catch(error => reject(error));
});
}
这是sqlCreatePlaylist的样子
INSERT INTO playlists(
user_id,
title,
playlist_type,
number_of_tracks,
duration,
description,
release_date
)
VALUES(
${userId},
${title},
${playlistType},
${numberOfTracks},
${lengthInSeconds},
${description},
${releaseDate}
)
RETURNING *;
答案 0 :(得分:2)
仅插入非空值:
insert into playlist_genre (playlist_id, genre_id)
select playlist_id, genre_id
from (values
(${playlistid}, ${genre1id}),
(${playlistid}, ${genre2id}),
(${playlistid}, ${genre3id})
) s (playlist_id, genre_id)
where genre_id is not null