Question

为了产生努力预测，我需要结合＆＃34;预订时间＆＃34; （此处：sapactivities）和＆＃34;计划时间＆＃34; （这里：计划活动）。输出应包含唯一日/资源/通知组合所花费的每日总时数，优先考虑＆＃34;预订＆＃34;超过＆＃34;计划＆＃34;时间。

SELECT date_format(result.CurrentDate, '%a, %d.%m.%Y'), 
   result.Resource, result.Notification, result.Hours, result.Effort 
FROM
(SELECT sapactivities.start AS 'CurrentDate',
        sapactivities.activitytext AS 'Resource',
        sapactivities.notification AS 'Notification',
        SUM(TIMESTAMPDIFF(MINUTE,start,end)/60) AS 'Hours',
        'Booked' AS 'Effort'
    FROM work.sapactivities 
    GROUP BY sapactivities.notification,sapactivities.activitytext,sapactivities.start

UNION ALL

SELECT plannedactivities.activitydate AS 'CurrentDate',
    /*CONCAT_WS(' ',resource.firstname,resource.lastname) AS 'Resource',*/
    resource.sapActivityText AS 'Resource',
    notification.notification AS 'Notification',
    plannedactivities.hours AS 'Hours',
    'Planned' AS 'Effort'
FROM work.plannedactivities
LEFT JOIN work.notification ON plannedactivities.idNotification = notification.id
LEFT JOIN work.resource ON plannedactivities.idResource = resource.id) AS result
GROUP BY result.Resource, result.Notification, DATE (result.CurrentDate), 
  CASE WHEN result.Effort = 'Booked' THEN 'Booked' ELSE 'Planned' END
ORDER BY result.Resource,result.CurrentDate ASC;

但是我仍然可以通过＆＃34; Booked＆＃34;获得日/资源/通知的重复行。和＆＃34;计划＆＃34;努力。我尝试了外部GROUP BY子句的多种方法，但是没有得到我正在寻找的结果......任何想法？

Answer 1

你的CASE不应该像这样在SELECT语句中吗？

SELECT 
date_format(result.CurrentDate, '%a, %d.%m.%Y'), 
result.Resource, result.Notification, result.Hours, 
(CASE WHEN result.Effort = 'Booked' THEN 'Booked' ELSE 'Planned' END) 
FROM ...

顺便说一句，你只是加入了一列，不应该在联合之前在两列上做左连接吗？

希望它有所帮助......如果我们有真正的信息来尝试它会好得多：D

Answer 2

通常可以使用ROW_NUMBER仿真完成，请参阅http://www.mysqltutorial.org/mysql-row_number/。如果'Booked'<'Planned'和Hours永远不会超过1000000，那么这个技巧就可以了

Select CurrentDate, Resource, Notification, min(Hours) MOD 100000, min(Effort) 
FROM (

    SELECT sapactivities.start AS 'CurrentDate',
            sapactivities.activitytext AS 'Resource',
            sapactivities.notification AS 'Notification',
            1000000 + SUM(TIMESTAMPDIFF(MINUTE,start,end)/60) AS 'Hours',
            'Booked' AS 'Effort'
        FROM work.sapactivities 
        GROUP BY sapactivities.notification,sapactivities.activitytext,sapactivities.start

    UNION ALL

    SELECT plannedactivities.activitydate AS 'CurrentDate',
        /*CONCAT_WS(' ',resource.firstname,resource.lastname) AS 'Resource',*/
        resource.sapActivityText AS 'Resource',
        notification.notification AS 'Notification',
        2000000 + plannedactivities.hours AS 'Hours',
        'Planned' AS 'Effort'
    FROM work.plannedactivities
    LEFT JOIN work.notification ON plannedactivities.idNotification = notification.id
    LEFT JOIN work.resource ON plannedactivities.idResource = resource.id

) AS result
GROUP BY result.Resource, result.Notification, DATE (result.CurrentDate)

根据条件输出没有重复日期的行

2 个答案: