我有3张桌子。如何根据这种情况显示cardNumber和相应的组。然后我可以创建一个视图并查看卡号以及它所属的组。
**1.ClientCards:**
1.1cardID
1.2cardNumber
1.2relCardTypeID - foreign key of 2.1cardTypeID
**2.cardTypes:**
2.1cardTypeID - foreign key of 3.1groupID
2.2relParrentID
2.2cardTypeName
**3.cardGroups:**
3.1groupID
3.1groupName
答案 0 :(得分:0)
希望您的映射错误,因为relParrentID应该是3.1 groupID的外键
试试这个:
#include <vector>
#include <stdlib.h>
#include <cstdlib>
#include <string>
#include <vector>
#include <fstream>
#include <sstream>
#include <iostream>
using namespace std;
class SimpleImageEffect
{
public:
virtual void processImage(vector<Point> &points) = 0;
};
class RemoveRed : public SimpleImageEffect
{
public:
virtual void processImage(vector<Point> &points)
{
for (Point& p : points)
{
p.setRed(0);
}
}
};
//Just an example of one of the effect classes.
//The code in them is correct, so I won't include the others unless needed.
vector<Point> parse_line(string line)
{
istringstream scanner{line};
vector<Point> result{};
int red = -1;
int green = -1;
int blue = -1;
int counter = 0;
while(scanner.good())
{
if (counter == 0)
{
counter++;
scanner >> red;
}
else if (counter == 1)
{
counter++;
scanner >> green;
}
else if (counter == 2)
{
scanner >> blue;
Point p{ red, green, blue };
result.push_back(p);
counter = 0;
}
}
return result;
}
void readFromCin()
{
string line = "";
vector<string> lines_in_file{};
int i, effect_choice;
SimpleImageEffect *effect = nullptr;
getline(cin, line);
while (line.length() > 0)
{
lines_in_file.push_back(line);
getline(cin, line);
}
for (int i = 0; i < lines_in_file.size(); i++)
{
if (lines_in_file[i] != "P3")
{
effect_choice = strToInt(lines_in_file[i]);
}
else if (lines_in_file[i] == "P3")
{
cout << lines_in_file[i] << endl;
cout << lines_in_file[i+1] << endl;
cout << lines_in_file[i+2] << endl;
}
vector<Point> points = parse_line(lines_in_file[i]);
if (effect_choice == 1) effect = new RemoveRed;
if (effect_choice == 2) effect = new RemoveGreen;
if (effect_choice == 3) effect = new RemoveBlue;
if (effect_choice == 4) effect = new NegateRed;
if (effect_choice == 5) effect = new NegateGreen;
if (effect_choice == 6) effect = new NegateBlue;
if (effect_choice == 7) effect = new AddNoise;
if (effect_choice == 8) effect = new HighContrast;
if (effect_choice == 9) effect = new ConvertToGrayscale;
effect->processImage(points);
for (auto p : points)
{
cout << p;
cout << endl;
}
}
}
int main(int argc, char** argv)
{
string menu_choice;
getline(cin, menu_choice);
if (menu_choice == "1")
{
readFromFile();
}
else
{
readFromCin();
}
return 0;
}
答案 1 :(得分:0)
VIEW `card_groups` AS
SELECT
`c`.`cardNumber` AS `cardNumber`,
`g`.`groupName` AS `groupName`,
`t`.`cardTypeName` AS `cardTypeName`
FROM
((`s2_1_cards` `c`
LEFT JOIN `fxml4_4_card_types` `t` ON ((`c`.`relCardTypeID` = `t`.`cardTypeID`)))
LEFT JOIN `fxml4_3_groups` `g` ON ((`g`.`groupID` = `t`.`relParrentID`)))