Question

我想要一个动画，我将随机的左侧和顶部值分配给div并为它们设置动画，但也希望动画在完成后重新启动。所以我在其自身内部启动了animate函数，但在第一个动画之后，只有最后一个重复div元素是动画。我确实喜欢这个：

function getRandomArbitrary(min, max) {
    return Math.random() * (max - min) + min;
}

$(".dot").each(function(){

    var abc = getRandomArbitrary(0,100);
    var xyz = getRandomArbitrary(0,100);
    var aaa = getRandomArbitrary(0,100);
    var yyy = getRandomArbitrary(0,100);
    $(this).css({"left": abc+"%", "top": xyz+"%"})
    $thiss = $(this);
    for(var i=0; i< $(".dot").length;i++){
        function anim(){
            $thiss.animate({"left":yyy+"%", "top": aaa+"%"},1000,function(){
                anim();
            });
            console.log(i)
        }
    }
    anim();
});

HTML：

<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>

的CSS：

.dot{width: 8px; height: 8px; border-radius: 100%; background: red; position: absolute;}

jsfiddle：https://jsfiddle.net/qfcmfzw7/ 我没有使用'for'的小提琴：https://jsfiddle.net/744sx34v/

Answer 1

将功能移至单独的功能并在循环中调用它：

＆＃13;

function getRandomArbitrary(min, max) {
      return Math.random() * (max - min) + min;
    }
    
    function anim(object){
    
    	   var aaa = getRandomArbitrary(0,100);
         var yyy = getRandomArbitrary(0,100);

         object.animate({"left":yyy+"%", "top": aaa+"%"},1000,function(){
              anim(object);
         });
     }
         
     $(".dot").each(function(){
     
        // set the initial position of each div
        var abc = getRandomArbitrary(0,100);
        var xyz = getRandomArbitrary(0,100);
    	  $(this).css({"left": abc+"%", "top": xyz+"%"});
        
        // call the animate function which calls itself recursively
    	  anim($(this));
     });

＆＃13;

.dot{width: 8px; height: 8px; border-radius: 100%; background: red; position: absolute;}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>

＆＃13;

Answer 2

您不需要for循环，需要递归调用animate()以获取特定元素，该元素也随机设置top和left CSS属性。

＆＃13;

function getRandomArbitrary(min, max) {
  return Math.random() * (max - min) + min;
}

$(".dot").each(function() {
  //Initially set left and top afterwards animate will take care of it
  var left = getRandomArbitrary(0, 100);
  var top = getRandomArbitrary(0, 100);
  $this = $(this);
  $this.css({
    "left": left + "%",
    "top": top + "%"
  })
  animate($this);
});

function animate($this) {
  var left = getRandomArbitrary(0, 100);
  var top = getRandomArbitrary(0, 100);
  $this.animate({
    "left": left + "%",
    "top": top + "%"
  }, 1000, function() {
    animate($this);
  });
}

＆＃13;

.dot {
  width: 8px;
  height: 8px;
  border-radius: 100%;
  background: red;
  position: absolute;
}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>
<div class="dot"></div>

＆＃13;

每个循环中的最后一个元素

2 个答案: