如何从android中的服务器检索以下json数据?能指导我一个例子吗?如何从下面的URL获取UserRole?
答案 0 :(得分:2)
以下是从服务器
中检索json数据的示例将Gson库的这种依赖关系添加到App的gradle:
compile 'com.google.code.gson:gson:2.4'
创建模型类
public class UserModel{
public String UserRole;
public String UserName;
public int Id;
public String Email;
public String getUserRole(){
return UserRole;
}
public void setUserRole(String _userRole){
UserRole = _userRole;
}
public String getUserName(){
return UserName;
}
public void setUserName(String _userName){
UserName = _userName;
}
public int getId(){
return Id;
}
public void setId(int _id){
Id = _id;
}
public String getEmail(){
return Email;
}
public void setEmail(String _email){
Email = _email;
}
}
现在使用Gson库从服务器对上述模型的响应转换数据。(注意:在AsyncTask类的onPostExecute()中写下这些行)
@Override
protected void onPostExecute(final Boolean success) {
try {
if (success) {
if (responsecode == 200) {
//GSON responsedata
if(responsedata!=null) {
if (responsedata != "") {
List<UserModel> userlist = new ArrayList<UserModel>();
JSONArray jsonArray = new JSONArray(responsedata);
for (int i = 0; i < jsonArray.length(); i++) {
UserModel item = new UserModel();
item = new Gson().fromJson(jsonArray.getJSONObject(i).toString(), UserModel.class);
userlist.add(item);
}
}
}
} else if(responsecode==401){
// use toast display the specific error
}
}
else {
Toast.makeText(context, responsedata, Toast.LENGTH_LONG).show();
}
} else {
Toast.makeText(context, "Access denied!", Toast.LENGTH_LONG).show();
}
}
catch (Exception e){
if(e!=null){
}
}
}
答案 1 :(得分:1)
你正在回复json数组。您可以从以下数组中获取详细信息:
try {
JSONArray jsonArray = new JSONArray(response);
for (int i=0; i<jsonArray.length();i++) {
JSONObject jsonObject = jsonArray.getJSONObject(i);
String userRole = jsonObject.getString("UserRole");
//Rest of the code....
}
} catch (Exception e) {
e.printStackTrace();
}
答案 2 :(得分:1)
使用以下代码获取JsonRespone:
class RetrieveFeedTask extends AsyncTask<Void, Void, String> {
protected void onPreExecute() {
responseView.setText("");
}
protected String doInBackground(Void... urls) {
String API_URL = "http://beta.json-generator.com/api/json/get/4y2NmxAYf";
// Do some validation here
try {
URL url = new URL(API_URL);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
try {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
StringBuilder stringBuilder = new StringBuilder();
String line;
while ((line = bufferedReader.readLine()) != null) {
stringBuilder.append(line).append("\n");
}
bufferedReader.close();
return stringBuilder.toString();
}
finally{
urlConnection.disconnect();
}
}
catch(Exception e) {
Log.e("ERROR", e.getMessage(), e);
return null;
}
}
protected void onPostExecute(String response) {
if(response == null) {
response = "THERE WAS AN ERROR";
}
// progressBar.setVisibility(View.GONE);
Log.i("INFO", response);
responseView.setText(response);
parseJsonData(response);
}
}
使用以下方法解析数据:
private void parseJsonData(String jsonResponse){
try
{
JSONArray jsonArray = new JSONArray(jsonResponse);
for(int i=0;i<jsonArray.length();i++)
{
JSONObject jsonObject1 = jsonArray.getJSONObject(i);
String UserRole = jsonObject1.optString("UserRole");
String UserName = jsonObject1.optString("UserName");
String Id = jsonObject1.optString("Id");
String Email = jsonObject1.optString("Email");
}
}
catch (JSONException e)
{
e.printStackTrace();
}
}
从链接下面找到API调用代码:
答案 3 :(得分:1)
您可以使用OkHttp从服务器获取json数据并使用fastjson来解析数据。 将这些依赖项添加到App的build.gradle:
compile 'com.alibaba:fastjson:1.2.24'
compile 'com.squareup.okhttp3:okhttp:3.6.0'
compile 'com.squareup.okio:okio:1.11.0'
然后1.创建一个模型类:
public class JsonModel {
private String UserRole;
private String UserName;
private int Id;
private String Email;
public String getUserRole() {
return UserRole;
}
public void setUserRole(String UserRole) {
this.UserRole = UserRole;
}
public String getUserName() {
return UserName;
}
public void setUserName(String UserName) {
this.UserName = UserName;
}
public int getId() {
return Id;
}
public void setId(int Id) {
this.Id = Id;
}
public String getEmail() {
return Email;
}
public void setEmail(String Email) {
this.Email = Email;
}
@Override
public String toString() {
return "JsonModel{" +
"Email='" + Email + '\'' +
", UserRole='" + UserRole + '\'' +
", UserName='" + UserName + '\'' +
", Id=" + Id +
'}';
}
2.使用OkHttp获取json数据并使用fastjson解析数据。
class GetJson extends Thread {
private String url;
public GetJson(String url) {
this.url = url;
}
@Override
public void run() {
OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder().url(url).build();
try {
Response response = client.newCall(request).execute();
if (response.isSuccessful()) {
final String text = response.body().string();
List<JsonModel> models = JSON.parseArray(text, JsonModel.class);
//Do other things based on models
}
} catch (IOException e) {
e.printStackTrace();
}
}
答案 4 :(得分:0)
您可以查看http://www.androidhive.info/2012/01/android-json-parsing-tutorial/并尝试在下次开始新主题之前搜索更多内容!
答案 5 :(得分:0)
试试这个,
StringRequest stringRequest = new StringRequest(Request.Method.GET,"http://beta.json-generator.com/api/json/get/4y2NmxAYf",
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONArray result = new JSONArray(response);
for (int i = 0; i < result.length(); i++)
{
JSONObject c = result.getJSONObject(i);
String UserRole = c.getString("UserRole");
String UserName = c.getString("UserName");
int Id = c.getInt("Id");
String Email = c.getString("Email");
}
} catch (JSONException e) {
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
}
});
RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);
您的Android项目的应用模块的gradle依赖项:
compile 'com.android.volley:volley:1.0.0'