Question

我有两个批处理脚本：

Batch_A

echo You are in Batch A
call "%~dp0Batch_B.bat" BAR

Batch_B

:FOO
echo You are in Batch A and you have failed.
:BAR
echo You are in Batch A and you have succeeded.

对于我的生活，无论我采用哪种方式进行语法化，第一批中的第2行都不会调用＆＃34; BAR＆＃34; Batch_B中的子程序。

我已经尝试过：

 call "%~dp0Batch_B.bat BAR"
 call "%~dp0Batch_B.bat" :BAR
 call "%~dp0Batch_B.bat" %BAR%
 call %~dp0Batch_B.bat BAR

没有任何作用。我知道这可能是一些基本的东西，但我做错了什么？有没有其他方法可以实现这个目标？

Answer 1

据我所知，你不能在另一个批处理文件中调用标签。你能做的是以下几点：

Batch_B.bat中的

：

Goto %~1
:FOO
echo You are in Batch A and you have failed.
:BAR
echo You are in Batch A and you have succeeded.

在Batch_A.bat

中

call "%~dp0Batch_B.bat" BAR

因此，这将在Batch_B.bat中评估为Goto Bar，然后转到第二个标签。

除此之外，您应在Goto eof部分结束后添加:FOO，这样您就不会通过:BAR部分。

Answer 2

这是可能的，但如果它是一个功能或错误，它就会受到争议。

::Batch_A.bat
@Echo off
echo You are in (%~nx0)
call :BAR
timeout -1
Goto :Eof
:BAR
echo You are in (%~nx0) (%0)
:: this runs's the batch without a call
"%~dp0Batch_B.bat" %*

:: Batch_B.bat
Goto :Eof
:FOO
echo You are in (%~nx0) and you have failed. 
Goto :Eof
:BAR
echo You are in (%~nx0) and you have succeeded.
Goto :Eof

> batch_a
You are in (Batch_A.bat)
You are in (Batch_A.bat) (:BAR)
You are in (Batch_B.bat) and you have succeeded.

批处理脚本中的调用不会转到另一个批处理文件中的指定子例程

2 个答案: