Question

抱歉我的英文。如果我错了，请纠正我。这个函数在firefox中正确执行但目标浏览器是chrome，我不知道错误

myjs.js

function addProduct(order_id) {
  $.ajax({
    type: "post",
    data: $("#formProducts").serialize(),
    url: "/save/" + order_id,
    complete: function(){}
  });
  $.ajax({
    type: "get",
    url: "/add/product/" + order_id,
    complete: function(){
      window.location.reload()
    },
  });
}

views.py

def post(self, request: HttpRequest, *args, **kwargs):
        order = Order.objects.get(id=int(kwargs['order_id']))
        try:
            comment = Comment.objects.get(order=order)
            comment.text = request.POST['comment']
        except Exception as _:
            comment = Comment(text="", order=order)
        comment.save()
        for key, val in request.POST.items():
            if "status" in key:
                idp = int(key.split("status")[1])
                product = Product.objects.get(id=idp)
                product.status = val
                product.save()
            elif "provider" in key:
                idp = int(key.split("provider")[1])
                product = Product.objects.get(id=idp)
                product.provider = val
                product.save()
            elif "med" in key:
                idp = int(key.split("med")[1])
                product = Product.objects.get(id=idp)
                product.name = val
                product.save()
            elif "amount" in key:
                idp = int(key.split("amount")[1])
                product = Product.objects.get(id=idp)
                product.amount = val
                product.save()
            elif "cost" in key:
                idp = int(key.split("cost")[1])
                product = Product.objects.get(id=idp)
                product.cost = val
                product.save()
            elif "ITOG" in key:
                order.summary = val
                order.save()
        url_ref = request.session["url_ref"]
        return redirect(url_ref)

def addProduct(request: HttpRequest, order_id):
    order = Order.objects.get(id=int(order_id))
    product = Product(name="", amount=1, cost=0.0, order=order)
    product.save()
    return HttpResponse()

函数必须收集formdata并发布它。然后make get request并重新加载页面。 Chrome可以实现，但重新加载页面后我看不到保存的数据，我必须重新加载页面，然后才能看到保存数据。

谢谢你的宁静。你的答案是对的

Answer 1

您可以使用此结构

 $(document).on('click','.sendwork',function(e){
       $.ajax({
        type: "post",
        data: $("#formProducts").serialize(),
        url: "/save/" + order_id,
        complete: function(){}
      });
      $.ajax({
        type: "get",
        url: "/add/product/" + order_id,
        complete: function(){
        },
      });
      window.location.reload()
    });

Chrome不能正确执行js，但firefox会执行此操作

1 个答案: