我试图在php脚本中获取已编码为json的数据。
我的代码:
func getJson(completion: @escaping (Array<CarPark>) -> Void) {
activityIndicatior.center = self.view.center
activityIndicatior.hidesWhenStopped = true
activityIndicatior.activityIndicatorViewStyle = UIActivityIndicatorViewStyle.gray
view.addSubview(activityIndicatior)
self.activityIndicatior.startAnimating()
let task = URLSession.shared.dataTask(with: url!) { (data, response, error) in
if error != nil
{
print("ERROR")
}
else
{
if let content = data
{
do{
let myJson = try JSONSerialization.jsonObject(with: content, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
for index in 0..<myJson.count {
if let entry = myJson[index] as? NSDictionary{
let name = entry["Name"] as! String
let longitude = Double(entry["Longitude"] as! String)
let latitude = Double(entry["Latitude"] as! String)
let quiet = Int(entry["Quiet"] as! String)
let moderate = Int(entry["Moderate"] as! String)
let busy = Int(entry["Busy"] as! String)
let coordinate = CLLocationCoordinate2D( latitude: latitude!, longitude: longitude!)
print("coordinate lat is : \(coordinate.latitude)")
print("coordinate long is : \(coordinate.longitude)")
print("coordinate full is: \(coordinate)")
let tempPark = CarPark(name: name, latitude: latitude!, longitude: longitude!, quiet: quiet!, moderate: moderate!, busy: busy!, coordinate: coordinate, level: "Nil")
let level = tempPark.calcAvailability()
tempPark.level = level
print("Availability is \(tempPark.level)")
self.tempCarParks.append(tempPark)
// print("amount of parks: \(self.carParks.count)")
print("name of parks in array: \(self.tempCarParks[index].name)")
print("Availability is \(tempPark.level)")
}
}
completion(self.tempCarParks)
}
catch
{
print("Error")
}
}
}
}
task.resume()
}
我收到的错误是“对下标的不明确使用”。在这一行:
如果让entry = myJson [index]为?的NSDictionary {
我该如何解决这个问题?
答案 0 :(得分:0)
既然您知道myJson
是一个数组,为什么要将对象转换为未指定的AnyObject
?
导致错误,编译器需要知道所有下标对象的具体类型。帮助编译器然后编译器帮助你:
let myJson = try JSONSerialization.jsonObject(with: content) as! [[String:Any]]
for entry in myJson { // don't use old-fashioned index based loops
let name = entry["Name"] as! String
...
.mutableContainers
在Swift中完全没用。