Question

我在ASP.NET中创建了一个Web请求，我需要向主体添加一堆数据。我该怎么做？

var request = HttpWebRequest.Create(targetURL);
request.Method = "PUT";
response = (HttpWebResponse)request.GetResponse();

Answer 1

使用HttpWebRequest.GetRequestStream

来自http://msdn.microsoft.com/en-us/library/d4cek6cc.aspx

的代码示例

string postData = "firstone=" + inputData;
ASCIIEncoding encoding = new ASCIIEncoding ();
byte[] byte1 = encoding.GetBytes (postData);

// Set the content type of the data being posted.
myHttpWebRequest.ContentType = "application/x-www-form-urlencoded";

// Set the content length of the string being posted.
myHttpWebRequest.ContentLength = byte1.Length;

Stream newStream = myHttpWebRequest.GetRequestStream ();

newStream.Write (byte1, 0, byte1.Length);

从我自己的代码之一：

var request = (HttpWebRequest)WebRequest.Create(uri);
request.Credentials = this.credentials;
request.Method = method;
request.ContentType = "application/atom+xml;type=entry";
using (Stream requestStream = request.GetRequestStream())
using (var xmlWriter = XmlWriter.Create(requestStream, new XmlWriterSettings() { Indent = true, NewLineHandling = NewLineHandling.Entitize, }))
{
    cmisAtomEntry.WriteXml(xmlWriter);
}

try 
{    
    return (HttpWebResponse)request.GetResponse();  
}
catch (WebException wex)
{
    var httpResponse = wex.Response as HttpWebResponse;
    if (httpResponse != null)
    {
        throw new ApplicationException(string.Format(
            "Remote server call {0} {1} resulted in a http error {2} {3}.",
            method,
            uri,
            httpResponse.StatusCode,
            httpResponse.StatusDescription), wex);
    }
    else
    {
        throw new ApplicationException(string.Format(
            "Remote server call {0} {1} resulted in an error.",
            method,
            uri), wex);
    }
}
catch (Exception)
{
    throw;
}

Answer 2

这应该有所帮助：

var request = (HttpWebRequest)WebRequest.Create("http://example.com/page.asp");

string stringData = ""; //place body here
var data = Encoding.ASCII.GetBytes(stringData); // or UTF8

request.Method = "PUT";
request.ContentType = ""; //place MIME type here
request.ContentLength = data.Length;

var newStream = request.GetRequestStream();
newStream.Write(data, 0, data.Length);
newStream.Close();

Answer 3

该主题的答案都很棒。但是我想提出另一个。您很可能已获得一个api，并希望将其纳入您的c＃项目中。使用Postman，您可以在那里设置和测试api调用，一旦它正常运行，您只需单击“代码”，然后将您一直在处理的请求写入c＃代码段。像这样：

var client = new RestClient("https://api.XXXXX.nl/oauth/token");
client.Timeout = -1;
var request = new RestRequest(Method.POST);
request.AddHeader("Authorization", "Basic   N2I1YTM4************************************jI0YzJhNDg=");
request.AddHeader("Content-Type", "application/x-www-form-urlencoded");
request.AddHeader("Content-Type", "application/x-www-form-urlencoded");
request.AddParameter("grant_type", "password");
request.AddParameter("username", "development+XXXXXXXX-admin@XXXXXXX.XXXX");
request.AddParameter("password", "XXXXXXXXXXXXX");
IRestResponse response = client.Execute(request);
Console.WriteLine(response.Content);

上面的代码取决于nuget软件包RestSharp，您可以轻松地安装它。

设置WebRequest的正文数据

3 个答案: