使用msgpack的ZeroMQ在C ++中抛出了无效的参数错误

Question

我正在使用zeromq从使用msgpack进行序列化的应用程序中读取数据。代码编译得很好但在运行时抛出了无效的参数错误。我哪里错了。

这是错误： 在抛出＆＃39; zmq :: error_t＆＃39;

的实例后终止调用

what（）：无效的参数 中止（核心倾销）

这是代码。

#include <zmq.hpp>
#include <iostream>
#include <sstream>
#include <msgpack.hpp>
#include <string>

int main(int argc, char *argv[]){
zmq::context_t context (1);

// Open a req port to talk to application
std::string addr = "tcp://127.0.0.1";
std::string req_port = "55555";
zmq::socket_t req (context, ZMQ_REQ);
req.connect(addr+req_port);

// Ask for the subport
zmq::message_t subPortRequest (8);
memcpy (subPortRequest.data(), "SUB_PORT", 8);
req.send(subPortRequest);

zmq::message_t reply;
req.recv(&reply);

std::string sub_port = std::string(static_cast<char*>(reply.data()), reply.size());
std::cout << sub_port << std::endl;


//  Open a sub port to listen to application
zmq::socket_t sub (context, ZMQ_SUB);
std::cout << addr+sub_port << std::endl;
sub.connect(addr+sub_port);

// subscriptions to everything
sub.setsockopt(ZMQ_SUBSCRIBE, "", strlen(""));

while(1){
    zmq::message_t reply_topic;
    sub.recv(&reply_topic);
    std::string topic = std::string(static_cast<char*>(reply_topic.data()), reply_topic.size());

    zmq::message_t reply_msg;
    sub.recv(&reply_msg);
    std::string msg = std::string(static_cast<char*>(reply_msg.data()), reply_msg.size());

    msgpack::object_handle oh = msgpack::unpack(msg.data(), msg.size());
    msgpack::object obj = oh.get();
    std::cout << obj << std::endl;

} 

}

Answer 1

string很可能无法满足规范：

虽然消息来源指示这样做：

zmq::socket_t req ( context, ZMQ_REQ );  // __________.SET [REQ] access point
// Open a req port to talk to application ____________.SET strings
std::string addr     = "tcp://127.0.0.1"; // _________.SET    "IP"-part
std::string req_port = "55555";           // _________.SET "PORT#"-part

req.connect( addr + req_port );           // _________.CONNECT( "IP"+"PORT#" )

ZeroMQ .connect() 方法应该得到一个关于这种形状的字符串：

  

<强> .connect( "tcp://127.0.0.1:55555" );
------------------------------- ----------------- ^

  

无论如何，享受使用ZeroMQ的强大功能构建智能分布式系统