Question

所以这个程序应该猜测你想到的数字。但是如果你运行它并在问你第一个问题之后再看，它就不再需要输入了。

#include <stdio.h>
#include <stdlib.h>

int main(){
printf("Enter the upper limit for the range of numbers:\n");
int n;
scanf("%d", &n);
int low=0;
int high=n;
printf("Answers should only be y for yes or n for no.\n");
do{
    int median;
    median=(high+low)/2;
    printf("Is your number greater than %d median?\n", median);
    char ans;
    scanf("%c", &ans);
    if(ans=='y' || ans=='Y'){
        low=median;
        continue;
    }
    else{
        printf("Is your number smaller than %d median?\n", median);
        scanf("%c", &ans);
        if(ans=='y' || ans=='Y'){
            high = median;
            continue;
        }
        else
        {
           low = high = median;
        }
        }
}while(low != high);
printf("Your number is: %d\n", low);
return 0;

}

Answer 1

试试这个：

scanf(" %c", &ans);

而不是

scanf("%c", &ans);

Answer 2

我认为您正在寻找一个猜测数字的程序，但您的代码似乎不是最佳方式。可以在一个循环和三个if-else语句中执行：如果匹配打印“祝贺”并打破循环，则查找更改上限或下限。

尝试这样的事情：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(void) 
{

int random_num = 0;
int guessed_num = 0;
int counter = 0; 
int lower = 0;
int upper;    

printf("Enter the upper range: ");
scanf("%d", upper);

srand(time(NULL));
random_num = rand() % upper + 1;

printf("Guess my number! "); 

    while(1)
    {
        counter++; 

        scanf("%d", &guessed_num);

        if (guessed_num == random_num) 
        {
            printf("You guessed correctly in %d tries! Congratulations!\n", counter); 
            break;
        }

        if (guessed_num < random_num) 
            printf("Your guess is too low. Guess again. ");

        if (guessed_num > random_num) 
            printf("Your guess is too high. Guess again. ");

    } 

return 0;   
}

如果您想坚持使用代码，我建议您使用getchar()函数代替scanf("%c", &ans)。您可以从link

了解有关它的更多信息

如何解决此程序中反复扫描的问题？

2 个答案: