Question

我将值id传递给javascript函数。其中id正在打印。

<script>
  function openModal(id) {
    document.getElementById('myModal').style.display = "block";
    var img_id = id;
    document.getElementById('caption').innerHTML = img_id;
  }
</script>

现在我想将此值传递给bootstrap模式

<div id="myModal" class="modal">
  <button type="button" id="close"  onclick="closeModal()">close</button>

  <div class="modal-content">
    <div class="mySlides">

    <?php    

    //here i want to use this id with if condition so that desired image is 
    //displayed.With for each all images are coming.
    //$project_images = explode(",", $value['project_gallery']);

    $project_images =  json_decode($value['project_gallery'],true); 

    foreach ($project_images as $project_image_value) {
    ?> 

    <img src="<?= base_url() ?>assets/uploads/projects/<? =$project_image_value['fname']?>" style="width:100%">

    <?php
    }
    ?>
   </div>
 </div>
</div>

是否有可能。如此，请告诉我。

Answer 1

在bootstrap模式中添加一个隐藏字段，如

EventBus.getDefault().postSticky(new SliderBusModel(SlideID,SlideImage,SlideType,SlideTitle));

并添加脚本

<input type="hidden" id="img_id" name="img_id">

}

因此，在模型中，您将获得一个字段img_id，其中包含您要传递的值

如何将id从javascript传递给codeigniter中的bootstrap模型？

1 个答案: