Question

我搜索了很多答案，但我只能找到多次添加一个项目的答案。或者只是将两个列表相乘。

#ratio of bar
ratio_variant1 = 0.1
ratio_variant2 = 0.3
ratio_variant3 = 0.4
ratio_variant4 = 0.2

ratio = []
ratio.extend([ratio_variant1, ratio_variant2, ratio_variant3, ratio_variant4])

#ratio to integer
ratiointeger = [x*100 for x in ratio]

#size of bar
size_variant1 = 2
size_variant2 = 3
size_variant3 = 4
size_variant4 = 6

size = []
size.extend([size_variant1, size_variant2, size_variant3, size_variant4])

bucket = size * ratiointeger

我担心我创建比率和大小列表的方式并不是真正的pythonic，但主要问题是我无法创建列表/存储桶：

10 items of 2
30 items of 3
40 items of 4
20 items of 6

Answer 1

试试这个：

bucket = [[s] * int(r) for (s, r) in zip(size, ratiointeger)]

Answer 2

在我看来，你需要：

>>> [[s]*r for s, r in zip(size, ratiointeger)]
[[2, 2, 2, 2, 2, 2, 2, 2, 2, 2], [3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3], [4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4], [6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6]]

这将构建一个列表列表，其中包含您想要的重复：

#ifndef TESTCLASS_H
#define TESTCLASS_H

#include <QObject>
#include <QMap>
#include <QColor>

class TestClass : public QObject
{
    Q_OBJECT
public:
    explicit TestClass(QObject *parent = 0);

    // mutators
    void setColor(const QString& aName, const QColor& aColor);
    QColor getColor(const QString &aName) const;

private:
    QMap<QString, QColor> mColors;
};

#endif // TESTCLASS_H

然后使用the method from this post展平它们。

根据变量将多个项目附加到列表中？

2 个答案: