Question

我试图在PHPSpec中为一个函数创建一个测试，该函数调用具有不同参数的另一个对象上的函数。到目前为止，我的尝试已经导致了几个不同的错误，所以我将概述到目前为止的情况。

最近的错误：

- it should find all realm data
  method call:
    - fetch(LeagueOfData\Adapters\Request\RealmRequest:000000001212f67d000000001262e5c6 Object (
      'apiDefaults' => Array &0 (
          'region' => 'euw'
      )
      'format' => null
      'data' => null
      'query' => null
      'where' => Array &0
  ))
  on Double\AdapterInterface\P51 was not expected, expected calls were:
    fetch(exact(Double\RequestInterface\P50:000000001212f607000000001262e5c6 Object (
      'objectProphecy' => Prophecy\Prophecy\ObjectProphecy Object (*Prophecy*)

PHPSpec文件：

class JsonRealmsSpec extends ObjectBehavior
{
    function let(AdapterInterface $adapter, LoggerInterface $logger, RequestInterface $request)
    {
        // fetch called with multiple request objects but we're not interested in the exact data it returns yet.
        $adapter->fetch($request)->willReturn(['test data']);
        $this->beConstructedWith($adapter, $logger);
    }

    function it_should_find_all_realm_data()
    {
        $this->findAll()->shouldReturnArrayOfRealms();
    }


    function getMatchers()
    {
        return [
            'returnArrayOfRealms' => function($realms) {
                foreach ($realms as $realms) {
                    if (!$realm instanceof Realm) {
                        return false;
                    }
                }
                return true;
            }
        ];
    }
}

正在测试的实际功能：

class JsonRealms implements RealmService
{
    const REGIONS = ['euw', 'eune', 'na'];

    private $source;
    private $log;
    private $realms;

    public function __construct(AdapterInterface $adapter, LoggerInterface $log)
    {
        $this->source = $adapter;
        $this->log = $log;
    }

    public function findAll() : array
    {
        $this->realms = [];
        foreach (self::REGIONS as $region) {
            $request = new RealmRequest(['region' => $region]);
            $response = $this->source->fetch($request);
            $this->realms[] = new Realm($realm['cdn'], $realm['v'], $region);
        }
        return $this->realms;
    }
}

我确定我可能遗漏了一些非常明显的东西，但对于我的生活，我现在看不到它。

Answer 1

所以事实证明我错过了一些明显的东西，我试图用一个模拟调用来解决它，而不是每个案例都有一个：

function let(AdapterInterface $adapter, LoggerInterface $logger) {
    $request = new RealmRequest(['region' => 'euw']);
    $adapter->fetch($request)->willReturn([
        'cdn' => 'http://test.url/euw',
        'v' => '7.4.3'
    ]);
    $request = new RealmRequest(['region' => 'eune']);
    $adapter->fetch($request)->willReturn([
        'cdn' => 'http://test.url/eune',
        'v' => '7.4.3'
    ]);
    $request = new RealmRequest(['region' => 'na']);
    $adapter->fetch($request)->willReturn([
        'cdn' => 'http://test.url/na',
        'v' => '7.4.3'
    ]);
}

这适当地设置了模拟适配器，以便我们可以测试服务是否正确创建了Realm对象。

如何通过更改PHPSpec中的参数来模拟多次调用的函数调用？

1 个答案: