Ramda：如何使用过滤功能保持原始结构

Question

我想做一个过滤功能，如下所示：

配置：

const arr = {
  id: 888,
  name: 'Library',
  bookLists: [{
      "name": "Book 1",
      "booked": "Y"
    }, {
      "name": "Book 2",
      "booked": "N"
    }, {
      "name": "Book 3",
      "booked": "Y"
    }]
  };

然后我尝试使用标记＆＃39;预订=== Y＆＃39;

过滤图书清单

R.compose(R.filter(x => x.booked === 'Y'), R.prop('bookLists'))(arr)

我得到了结果，这是正确的

[{"booked": "Y", "name": "Book 1"}, {"booked": "Y", "name": "Book 3"}]

然而，这是我想要的一部分。我怎样才能达到这样的结果？

{
  id: 888,
  name: 'Library',
  bookLists: [{
      "name": "Book 1",
      "booked": "Y"
    }, {
      "name": "Book 3",
      "booked": "Y"
    }]
  }

Answer 1

您可以使用R.evolve：

R.evolve({bookLists: R.filter(x => x.booked === 'Y')})(arr)

结果将是：

{
  id: 888,
  name: 'Library',
  bookLists: [{
      "name": "Book 1",
      "booked": "Y"
    }, {
      "name": "Book 3",
      "booked": "Y"
    }]
  }

参见相关的DOCS here。