在我的Web应用程序中,我使用的是asp.net mvc5和angular1.5。所有视图都使用ui-view呈现为部分视图。 我需要将DevExpress报告与mvc5和angular js集成。 有没有人知道如何将DevExpress报告与mvc5和angularjs 1.5集成。
答案 0 :(得分:1)
请查看以下关于您问题的链接,目前的解决方案是为报告查看器设置单独的页面,您可以使用iframe在应用内显示
https://www.devexpress.com/Support/Center/Question/Details/T289424 https://www.devexpress.com/Support/Center/Question/Details/T422061
快乐编码:)
答案 1 :(得分:1)
此方法可帮助您动态选择报表和数据。我试过了。
Angularview。
<div ng-app="DemoApp" ng-controller="DemoController">
<table style="width:100%;height:100%;">
<tr>
<td style="background-color:gray;width:20%;vertical-align: top;text-align: left;">
<h3>Select report tamplates</h3>
<ul>
<li ng-repeat="r in reports"><h6 ng-click="reportSelected(r.type)">{{r.type}}</h6></li>
</ul>
</td>
<td style="background-color:forestgreen;">
<iframe src="/Home/Index" style="width:100%;height:800px" id="viewer"></iframe>
</td>
</tr>
</table>
</div>
家庭控制器。
public class HomeController : Controller
{
public ActionResult Index()
{
//i am getting some parameter from angular by query string and acordingli decide with report template and data need to add.
var type = Request.QueryString["Type"];//parameter from angular
if (type != null)
{
type.Trim();
}
else { type = "Xm"; }
if (type.Equals("Pipe"))
{
ViewBag.Path = @"report path";
ViewBag.Data = "data json in my case";
}
else
{
ViewBag.Path = @"aspx report path";//you can specify this report at runtime
ViewBag.Data = //json data in my case,you can add any data wicht impliments ILIST or related interfaces;
}
return View();
}
}
索引视图(生成报告)。
@{
ViewBag.Title = "Home Page";
}
@Html.DevExpress().WebDocumentViewer(settings =>
{
settings.Name = "WebDocumentViewer";
}).Bind((new DXWebApplication1.Reports.Class1(@ViewBag.Path, @ViewBag.Data)).getReport()).GetHtml()
//(DXWebApplication1.Reports.Class) this class is created to return report
返回报告的类。
DXWebApplication1.Reports.Class
public class Class1
{
public DevExpress.XtraReports.UI.XtraReport report { get; set; }
public Class1(string filepath, string datasource)
{
this.report = new DevExpress.XtraReports.UI.XtraReport();
this.report.LoadLayout(filepath);
this.report.DataSource = JsonConvert.DeserializeObject<List<JobCode>>(datasource);
}
public DevExpress.XtraReports.UI.XtraReport getReport()
{
return this.report;
}
因为正在使用休息服务我将json反序列化为c#类以进行报告。
C#类反序列化json数据。
class JobCode
{
[JsonProperty("Description")]
public string Description { get; set; }
[JsonProperty("Size")]
public int Size { get; set; }
[JsonProperty("Weight")]
public int Weight { get; set; }
[JsonProperty("name")]
public string Name { get; set; }
}