我使用PostgreSQL,如果它超出范围,我很乐意修剪日期。
首先,我喜欢将记录过滤掉。 下面的查询并不困难。 (过滤2017/3/1~2017 / 3/31)
select * from subscriptions where current_period_start_at <= date '2017/03/01' AND current_period_end_at >= date '2017/03/31'
但是,如果超出范围(2017-03-1 ~ 2017-03-31
),我希望切断日期。
current_period_start_at:2017/02/25
=&gt; 2017/03/01
current_period_end_at:2017/04/02
=&gt; 2017/03/31
这是一些例子。
target 2016/08/05 ~ 2016/09/15
range① 2016/07/01 ~ 2016/08/31 => 2016/08/05 ~ 2016/08/31
range② 2016/08/10 ~ 2016/09/20 => 2016/08/10 ~ 2016/09/15
range③ 2016/09/15 ~ 2016/10/10 => x out of the scope
range④ 2016/08/01 ~ 2016/09/30 => 2016/08/05 ~ 2016/09/15
答案 0 :(得分:4)
您可以使用least()
函数获取较低的值:
select greatest(current_period_start_at, date '2016-08-05') as range_start,
least(current_period_end_at, date '2016-09-15') as range_end
from subscriptions
where (current_period_start_at,current_period_end_at)
overlaps (date '2016-08-05', date '2016-09-15');
如果您不想重复日期值,可以使用公用表表达式:
with range (r_start, r_end) as (
values (date '2016-08-05', date '2016-09-15')
)
select greatest(current_period_start_at, r_start) as range_start,
least(current_period_end_at, r_end) as range_end
from subscriptions, range
where (current_period_start_at,current_period_end_at)
overlaps (r_start, r_end);
答案 1 :(得分:3)
您应该尝试使用daterange数据类型。
SELECT daterange('2017-01-01'::date, '2017-03-01'::date) * daterange('2017-02-15'::date, '2017-05-01'::date);
返回
[2017-02-15,2017-03-01)