Question

我很少<?php if (isset($_POST['Btn'])) { echo "<p>".$_POST['Btn']."</p>"; } ?> <form action="somefile.php" method="POST"> <div class="form-group col-md-4"> <label>Sold Out</label> <div> <button data-toggle="collapse" name="btn" value="YES">YES </button> <button data-toggle="collapse" name="btn" value="NO">NO</button> </div> </div> </form>存储没有任何扩展程序：

如何打开它们？

Answer 1

with open('1', 'r') as fp:
    content = fp.read()

这样，文件将一直关闭。

Answer 2

要添加@ math2001的答案，你可以这样做：

numOfFiles = #int
data = []

for files in range(1, numOfFiles+1):
    with open(str(files), 'r') as f:
        // do whatever data processing you need to do
        fileData = f.read()
        data.append(fileData)

Answer 3

另一种方式：

import os
import glob
files = filter(os.path.isfile, glob.glob("./[0-9]*"))
for name in files:
    with open(name) as fh:
        contents = fh.read()
        # do something with contents (parse email format)

在python中打开Type文件的文件

3 个答案: