使用Kotlin处理Firebase数据库时,如果我使用List<String>
,我似乎无法检索GenericTypeIndicator
类型的值,如下所示:
snap.getValue(object : GenericTypeIndicator<List<String>>() {})
它从Firebase SDK中产生如下异常:
com.google.firebase.database.DatabaseException: Generic wildcard types are not supported
at com.google.android.gms.internal.zzbtg.zza(Unknown Source)
at com.google.android.gms.internal.zzbtg.zza(Unknown Source)
at com.google.android.gms.internal.zzbtg.zza(Unknown Source)
at com.google.android.gms.internal.zzbtg.zza(Unknown Source)
at com.google.firebase.database.DataSnapshot.getValue(Unknown Source)
但是,如果我从Java调用它,如下所示,它可以工作:
snap.getValue(new GenericTypeIndicator<List<String>>() {})
我猜它与类型修改有关,所以我这样做了:
inline fun <reified T> genericType() = object: GenericTypeIndicator<T>() {}
val stringListIndicator = genericType<List<String>>()
snap.getValue(stringListIndicator)
但发生了同样的例外。
为什么会这样?
编辑:我尝试使用jadx-0.6.1反编译Java和Kotlin版本。
Java来源:
public class Randommmm {
private static final GenericTypeIndicator<List<String>> ti = new GenericTypeIndicator<List<String>>() {
};
public static List<String> x(DataSnapshot snap) {
return snap.getValue(ti);
}
}
反编译:
public class Randommmm {
private static final GenericTypeIndicator<List<String>> ti = new C12761();
static class C12761 extends GenericTypeIndicator<List<String>> {
C12761() {
}
}
public static List<String> m48x(DataSnapshot snap) {
return (List) snap.getValue(ti);
}
}
Kotlin来源(1):
object Randommmm {
private val ti = object : GenericTypeIndicator<List<String>>() {
}
fun x(snap: DataSnapshot): List<String> {
return snap.getValue(ti)
}
}
反编译:
public final class Randommmm {
public static final Randommmm INSTANCE = null;
private static final Randommmm$ti$1 ti = null;
static class C12761 extends GenericTypeIndicator<List<String>> {
C12761() {
}
}
static {
Randommmm randommmm = new Randommmm();
}
private Randommmm() {
INSTANCE = this;
ti = new Randommmm$ti$1();
}
@NotNull
public final List<String> m48x(@NotNull DataSnapshot snap) {
Intrinsics.checkParameterIsNotNull(snap, "snap");
Object value = snap.getValue(ti);
Intrinsics.checkExpressionValueIsNotNull(value, "snap.getValue(ti)");
return (List) value;
}
}
public final class Randommmm$ti$1 extends GenericTypeIndicator<List<? extends String>> {
Randommmm$ti$1() {
}
}
Kotlin来源(2)使用道格建议的ArrayList
:
object Randommmm {
private val ti = object : GenericTypeIndicator<ArrayList<String>>() {
}
fun x(snap: DataSnapshot): List<String> {
return snap.getValue(ti)
}
}
反编译:
public final class Randommmm {
public static final Randommmm INSTANCE = null;
private static final Randommmm$ti$1 ti = null;
static class C12761 extends GenericTypeIndicator<List<String>> {
C12761() {
}
}
static {
Randommmm randommmm = new Randommmm();
}
private Randommmm() {
INSTANCE = this;
ti = new Randommmm$ti$1();
}
@NotNull
public final List<String> m48x(@NotNull DataSnapshot snap) {
Intrinsics.checkParameterIsNotNull(snap, "snap");
Object value = snap.getValue(ti);
Intrinsics.checkExpressionValueIsNotNull(value, "snap.getValue(ti)");
return (List) value;
}
}
public final class Randommmm$ti$1 extends GenericTypeIndicator<ArrayList<String>> {
Randommmm$ti$1() {
}
}
答案 0 :(得分:18)
在Kotlin,
http://a:8080
http://b:8080
生成为(在Java中):
val ti = object : GenericTypeIndicator<List<String>>() {}
请注意通配符SyntethicClass ti = new SyntethicClass();
public final class SyntethicClass extends GenericTypeIndicator<List<? extends String>> {}
,而不仅仅是普通? extends String
。
请参阅https://kotlinlang.org/docs/reference/java-to-kotlin-interop.html#variant-generics了解相关信息。
为了防止这种情况,请使用String
注释类型参数:
@JvmSuppressWildcards
这变得非常难看,但它确实有效。或者,根据Doug's answer使用val ti = object : GenericTypeIndicator<List<@JvmSuppressWildcards String>>() {}
。
答案 1 :(得分:3)
尝试更改此行:
snap.getValue(object : GenericTypeIndicator<List<String>>() {})
对此:
snap.getValue(object : GenericTypeIndicator<ArrayList<String>>() {})
它对我有用,但我不知道为什么。