Question

当我运行以下查询时：

SELECT 
    CASE 
       WHEN AT_EMPSCHEDULE.START1 <> '01/01/1900' 
            AND AT_EMPSCHEDULE.START2 <> '01/01/1900' 
            AND AT_EMPSCHEDULE.END2 <> '01/01/1900'
            AND AT_EMPSCHEDULE.LEAVECODE ='' 
            AND NOT EXISTS(SELECT PDATE 
                           FROM HR_PUBHOLIDAY 
                           WHERE PDATE=AT_EMPSCHEDULE.TRANDATE) 
            AND DATEPART(WEEKDAY,AT_EMPSCHEDULE.TRANDATE) <> 1 
          THEN 
             CAST((SELECT HIS_GENSALARYD.BASESALARY/HIS_GENSALARYD.WORKDAY 
                   FROM HIS_GENSALARYD 
                   WHERE (AT_EMPSCHEDULE.TRANDATE BETWEEN HIS_GENSALARYD.PAYFROM 
                                                  AND HIS_GENSALARYD.PAYTO 
                     AND HIS_GENSALARYD.EMPCODE = AT_EMPSCHEDULE.EMPCODE)) AS DECIMAL(10, 2)) 
          ELSE 0 
    END AS DAILYSALARY
FROM 
    HIS_GENSALARY 
INNER JOIN 
    AT_EMPSCHEDULE ON HIS_GENSALARY.EMPCODE = AT_EMPSCHEDULE.EMPCODE 
                   AND MONTH(TRANDATE) = HIS_GENSALARY.INMONTH 
                   AND YEAR(TRANDATE) = HIS_GENSALARY.INYEAR 
WHERE 
    HIS_GENSALARY.EMPCODE = HIS_GENSALARY.EMPCODE

我收到消息：

子查询返回的值超过1。当子查询遵循=，！=，＆lt;，＆lt; =，＆gt;，＆gt; =或子查询用作表达式时，不允许这样做。

Answer 1

问题在于：

(SELECT HIS_GENSALARYD.BASESALARY/HIS_GENSALARYD.WORKDAY 
 FROM HIS_GENSALARYD 
 WHERE AT_EMPSCHEDULE.TRANDATE BETWEEN HIS_GENSALARYD.PAYFROM 
     AND HIS_GENSALARYD.PAYTO 
 AND HIS_GENSALARYD.EMPCODE = AT_EMPSCHEDULE.EMPCODE)

您已用作表达式。根据错误消息，它必须永远生成一个结果，您已经使用过它;即它必须永远不会返回多行，但至少有一个调用返回了多行。

要强制它只返回一行，请对其应用聚合函数;一个明显的选择是max()：

(SELECT MAX(HIS_GENSALARYD.BASESALARY/HIS_GENSALARYD.WORKDAY)
 FROM HIS_GENSALARYD 
 WHERE AT_EMPSCHEDULE.TRANDATE BETWEEN HIS_GENSALARYD.PAYFROM 
     AND HIS_GENSALARYD.PAYTO 
 AND HIS_GENSALARYD.EMPCODE = AT_EMPSCHEDULE.EMPCODE)

当子查询遵循=，！=，＆lt;，＆lt; =，＆gt;，＆gt; =当我使用子查询

1 个答案: