Question

我的程序要求个人输入2个数字（即10和20）。我希望输出为：

偶数：10 12 14 16 18 20

我的代码：

  System.out.println("Enter an integer:");
  int firstNum = keyboard.nextInt();

  System.out.println("Enter another integer larger than the first one:");
  int secondNum = keyboard.nextInt();

  System.out.println();

  int mod = firstNum % 2;

  while ((firstNum < secondNum) && mod == 0)
  {
      firstNum = firstNum + 2;
      System.out.print("Even numbers" +firstNum);
  }

Answer 1

您接近您所追求的结果，只需要重新排列几行的顺序并添加一个if支票。

我已经制作了一个完整的示例，按预期运行并允许奇数和偶数。您可以使用以下代码替换代码：

public static void main(String[] args)
{
    Scanner keyboard = new Scanner(System.in);      
    System.out.println("Enter an integer:");
    int firstNum = keyboard.nextInt();

    System.out.println("Enter another integer larger than the first one:");
    int secondNum = keyboard.nextInt();

    System.out.println();

    int mod = firstNum % 2;
    //If first number is odd, increase by one to make it even.
    if (mod != 0)
    {
        firstNum++;
    }

    System.out.print("Even Numbers: ");
    while (firstNum <= secondNum)
    {
        System.out.print(firstNum + " ");
        firstNum = firstNum + 2;
    }
    keyboard.close();
}

如何在Java中将输入值增加2

1 个答案: