在项目/创建活动表单中,我将字段“相关公司帐户”作为下拉列表(select2 by kartik)。在此字段后面,我想添加一个加号或其他内容,以便在下拉列表中添加新帐户,但行为如下:
$input = compact(array_keys(get_defined_vars()));
,但客户端可能需要)return $this->redirect(Yii::$app->request->referrer);
)并填写先前输入的数据(extract($input, EXTR_PREFIX_SAME, "arr");
)我现在正在努力解决几个问题:
欢迎任何提示。提前谢谢。
答案 0 :(得分:1)
我建议使用Session。
对于“添加帐户”按钮,我会使用“提交”按钮,并为实际的“提交”按钮指定不同的名称(表单中有两个提交按钮,如here中所述)。因此,projects / create视图将如下所示:
<?php $form = ActiveForm::begin(); ?>
...
...
...
<?= $form->field($model, 'account_id')->widget(Select2::classname(), [
'data' => ArrayHelper::map(Account::find()->all(), "id", "name"),
'options' => ['placeholder' => 'Select a related company account ...'],
'pluginOptions' => [
'allowClear' => true
],
]) ?>
<?= Html::submitButton('Add Account ;)', ['class' => 'btn btn-success', 'name' => 'add_account_submit']) ?>
...
...
...
<div class="form-group">
<?= Html::submitButton($model->isNewRecord ? 'Create' : 'Update', ['class' => $model->isNewRecord ? 'btn btn-success' : 'btn btn-primary']) ?>
</div>
<?php ActiveForm::end(); ?>
然后检查ProjectsController,提交用户按下的按钮。如果按下了添加帐户,则保存输入的字段(我将此功能放入模型中以进行清除),否则,保存模型或任何其他内容。并且,在此之前,检查是否设置了关于项目的会话,如果是,则将其预加载到模型(再次,在模型中)。好吧,就像他们说的,一个代码值得千言万语,所以,这就是ProjectsController看起来像:
class ProjectsController extends Controller
{
...
...
...
public function actionCreate($category)
{
$model = new Projects();
if (Projects::isSavedInSession()) {
$model->loadFromSession();
}
if (Yii::$app->request->post('add_account_submit')) { // if add_account_submit is clicked
$model->saveTosession(Yii::$app->request->post('Projects')); // I assume your model named Projects, if not, change this value to your model name
return $this->redirect(['accounts/create']);
}
if ($model->load(Yii::$app->request->post()) && $model->save()) {
$model->clearSession(); // we dont need the session anymore
return $this->redirect(['index');
}
return $this->render('create', [
'model' => $model,
]);
}
...
...
...
}
项目模型将如下所示:
class Projects extends \yii\db\ActiveRecord
{
...
...
...
public static function isSavedInSession() { // why this is static is beyond this question context
if (Yii::$app->session->get('projects')) return true;
return false;
}
public function loadFromSession() {
if (Yii::$app->session->get('projects_name')) $this->name = if (Yii::$app->session->get('projects_name'));
if (Yii::$app->session->get('projects_account_id')) $this->account_id = if (Yii::$app->session->get('projects_account_id'));
...
... // insert all model's field here
...
}
public function saveToSession($fields) {
Yii::$app->session->set('projects', 1);
foreach ($fields as $field=>$value) {
Yii::$app->session->set('projects_' . $field, $value);
}
}
public function clearSession() {
Yii::$app->session->remove('projects'));
Yii::$app->session->remove('projects_name'));
Yii::$app->session->remove('projects_account_id'));
...
... // insert all model's field here
...
}
...
...
...
}
在AccountsController中,只需告诉程序跳回项目/创建项目会话是否已设置,如下所示:
class AccountsController extends Controller
{
...
...
...
public function actionCreate($category)
{
$model = new Accounts();
if ($model->load(Yii::$app->request->post()) && $model->save()) {
if (Projects::isSavedInSession()) {
return $this->redirect(['projects/create');
}
return $this->redirect(['index');
}
return $this->render('create', [
'model' => $model,
]);
}
...
...
...
}
嗯,它看起来有点长,但是,是值得尝试的。无论如何,您可以将此方法用于其他目的,例如保存当前表单状态。
哦,还有一件事,我还没有在实际代码中对此进行过测试,所以如果我的代码中出现任何错误,请发表评论。
快乐的编码。 :)