Question

我需要从昨天和一周前存储的数据库中选择结果。我可以在同一个查询中执行此操作吗？

SELECT *
FROM t1
WHERE DATE(t1recordDate) = CURDATE() - INTERVAL 1 DAY

和

SELECT *
FROM t1
WHERE DATE(t1recordDate) = CURDATE() - INTERVAL 7 DAY

Answer 1

您可以使用or逻辑运算符，或者更好的是，使用速记in：

SELECT *
FROM   t1
WHERE  DATE(t1recordDate) IN 
       (CURDATE() - INTERVAL 1 DAY, CURDATE() - INTERVAL 7 DAY)

Answer 2

如果您只需要昨天和之前的值，而不是范围内的天数，则可以使用OR和date_sub

SELECT *
FROM t1
WHERE DATE(t1recordDate) = DATE(DATE_SUB(CURDATE(),INTERVAL 1 DAY))
OR DATE(t1recordDate) = DATE(DATE_SUB(CURDATE(),INTERVAL 7 DAY))

如果你需要所有范围

SELECT *
FROM t1
WHERE DATE(t1recordDate) BETWEEN  DATE(DATE_SUB(CURDATE(),INTERVAL 7 DAY))
       AND  DATE(DATE_SUB(CURDATE(),INTERVAL 1 DAY))

Answer 3

如果你不喜欢这个简单的解决方案，你可以试试这个：

select t1.*
from (
    select 
        curdate() - interval 1 day as ts_from,
        curdate() - interval 1 second as ts_to
    union all
    select 
        curdate() - interval 7 day as ts_from,
        curdate() - interval 6 day - interval 1 second as ts_to
) as r
join t1 on t1.t1recordDate between r.ts_from and r.ts_to

http://rextester.com/PLVMY63927

它至少可以使用索引。

从昨天和一周前选择结果

3 个答案: