我是PHP的新手,iam尝试根据你在IF块中可以看到的条件为column4,column7,column9的单元格着色,下面是我尝试的代码,请帮助我理解如何实现这一点。我正在使用数组,因为我有超过80列,在下面的例子中,iam只显示10个用于解释。
<?php
$con=mysqli_connect("server","user","password","db");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM table1");
echo "<table id='table_id' class='mytable'>
<thead>
<tr>
<th class='heading'>Column1</th>
<th class='heading'>Column2</th>
<th class='heading'>Column3</th>
<th class='heading'>Column4</th>
<th class='heading'>Column5</th>
<th class='heading'>Column6</th>
<th class='heading'>Column7</th>
<th class='heading'>Column8</th>
<th class='heading'>Column9</th>
<th class='heading'>Column10</th>
</tr>
</thead>";
echo "<tbody>";
while ($row = mysqli_fetch_array($result))
{
$colorfields = array($row['Column4'],$row['Column7'],$row['Column9']);
if ($colorfields < 195 && $colorfields !='')
$classname = "red";
else if($colorfields >= 195 && $colorfields < 199.99)
$classname = "yellow";
else if($colorfields >= 199.99)
$classname = "green";
echo "<tr>";
echo "<td class='normal_cell'>" . $row['Column1']."</td>";
echo "<td class='normal_cell'>" . $row['Column2']."</td>";
echo "<td class='normal_cell'>" . $row['Column3']."</td>";
echo "<td class=".$classname.">". $row['Column4']."</td>";
echo "<td class='normal_cell'>" . $row['Column5']."</td>";
echo "<td class='normal_cell'>" . $row['Column6']."</td>";
echo "<td class=".$classname.">". $row['Column7']."</td>";
echo "<td class='normal_cell'>" . $row['Column8']."</td>";
echo "<td class=".$classname.">". $row['Column9']."</td>";
echo "<td class='normal_cell'>" . $row['Column10']."</td>";
echo "</tr>";
}
echo "</tbody>";
echo "</table>";
mysqli_close($con);
?>
答案 0 :(得分:2)
我会编写一个返回'red','yellow'或'green'的函数,具体取决于作为参数传入的值。
function class_from_val($val) {
$classname = '';
if( $val < 195 && $val !='' ) {
$classname = 'red';
} else if( $val >= 195 && $val < 199.99 ) {
$classname = 'yellow';
} else if( $val >= 199.99 ) {
$classname = 'green';
} else {
// ? val = ""
}
return $classname;
}
然后我会调用我需要返回类名的函数
echo "<td class='normal_cell'>" .$row['Column3']."</td>";
echo "<td class='".class_from_val($row['Column4'])."'>".$row['Column4']."</td>";
echo "<td class='normal_cell'>" .$row['Column5']."</td>";
echo "<td class='normal_cell'>" .$row['Column6']."</td>";
echo "<td class='".class_from_val($row['Column7'])."'>".$row['Column7']."</td>";
答案 1 :(得分:2)
遵循以下一般原则:
示例:
<div class="image-grid">
<div class="image-grid__image">
<img src="https://placehold.it/180x120/fff/000">
</div>
<div class="image-grid__image">
<img src="https://placehold.it/180x120/fff/000">
</div>
<div class="image-grid__image">
<img src="https://placehold.it/180x120/fff/000">
</div>
</div>