Question

所以这是我到目前为止的python代码。我想使用这些词典并将它们列入学生列表。我对如何将它们运行到getAverage()函数并生成此结果

无能为力

 Name: Alice
 Homework: [100.0, 92.0, 98.0, 100.0]
 Quizzes: [82.0, 83.0, 91.0]
 Tests: [89.0, 97.0]
 For Alice the average is:91.14999999999999 

Name: Lloyd
Homework: [90.0, 97.0, 75.0, 92.0]
Quizzes: [88.0, 40.0, 94.0]
Tests: [75.0, 90.0]
For Lloyd the average is:80.55 

Name: Tyler
Homework: [0.0, 87.0, 75.0, 22.0]
Quizzes: [0.0, 75.0, 78.0]
Tests: [100.0, 100.0]
For Tyler the average is:79.9

这是我到目前为止所做的代码：

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]}

rich = {
"name": "Rich",
"homework": [95.0, 93.0, 81.0, 94.0],
"quizzes": [88.0, 55.0, 77.0],
"tests": [80.0, 95.0]}

josh = {
"name": "Josh",
"homework": [93.0, 94.0, 74.0, 99.0],
"quizzes": [87.0, 47.0, 92.0],
"tests": [70.0, 88.0]}

def average(n):
    count = float(len(n))
    total = float(sum(n))

    return total/count

def getAverage(**names):
    homework = average(names[homework])
    quizzes = average(names[quizzes])
    tests = average[names[tests]]
    return float((.1*homework +.3*quizzes + .6*tests)/3)

students = [rich, josh, lloyd]

Answer 1

将getAverage函数修改为此（删除**）

def get_average(names):
    homework = average(names['homework'])
    quizzes = average(names['quizzes'])
    tests = average(names['tests'])
    return (0.1*homework + 0.3*quizzes + 0.6*tests) / 3

for student in [rich, josh, lloyd]:
    print student['name'], get_average(student)

其他几点：

您的average功能
更喜欢使用PEP8约定（特别是lower_case变量）

Answer 2

你很近但你需要做一些事情。首先从getAverage删除**。接下来删除返回时的/3。同时将此行[]上的外()更改为average[names[tests]]。然后修复缩进。

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]}

rich = {
"name": "Rich",
"homework": [95.0, 93.0, 81.0, 94.0],
"quizzes": [88.0, 55.0, 77.0],
"tests": [80.0, 95.0]}

josh = {
"name": "Josh",
"homework": [93.0, 94.0, 74.0, 99.0],
"quizzes": [87.0, 47.0, 92.0],
"tests": [70.0, 88.0]}

alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]}

taylor = {
"name": "Taylor",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]}

def average(n):
  count = float(len(n))
  total = float(sum(n))
  return total/count

def getAverage(names):
  homework = average(names['homework'])
  quizzes = average(names['quizzes'])
  tests = average(names['tests'])
  return float((.1*homework +.3*quizzes + .6*tests))

students = [rich, josh, lloyd, alice, taylor]
for student in students:
  avg=getAverage(student)
  print('Name: '+student['name'])
  print('Homework: '+str(student['homework']))
  print('Quizzes: '+str(student['quizzes']))
  print('Tests: '+str(student['tests']))
  print('For '+student['name']+' the average is: '+str(avg)+'\n')

函数如何获取字典参数

2 个答案: