wb = openpyxl.load_workbook(filename = 'C:/Users/test.xlsx')
sheet = wb['sheet1']
len=sheet.max_row
vals1 = [v[0].value for v in sheet.get_squared_range(1,1,2,len)]
vals2 = [v[1].value for v in sheet.get_squared_range(1,1,2,len)]
但我想要像
那样vals12 = [v[0].value,v[1].value for v in sheet.get_squared_range(1,1,2,len)]
其中vals12-是具有维度的矩阵(len x 2)
答案 0 :(得分:3)
rows_iter = sheet.get_squared_range(1, 1, 2, sheet.max_row)
vals = [[cell.value for cell in row] for row in rows_iter]
注意:强>
openpyxl
源代码指出已弃用get_squared_range()
,您应该使用iter_rows()
:
@deprecated(""" Use ws.iter_rows() or ws.iter_cols() depending whether you want rows or columns returned. """) [docs] def get_squared_range(self, min_col, min_row, max_col, max_row):
使用iter_rows()
执行:
rows_iter = sheet.iter_rows(min_col=1, min_row=1, max_col=2, max_row=sheet.max_row)
vals = [[cell.value for cell in row] for row in rows_iter]
答案 1 :(得分:0)
最简单的方法可能是:
values = [[cell.value for cell in col] for col in ws['A':'B']]
但您也可以在itertools.islice()
ws.values