Question

我想拆分这个对象数组。这只是整个阵列的一部分，其中包含未来两年的预订。

[ { state: 'BOOKED', date: 2017-01-01T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-02T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-03T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-04T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-05T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-06T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-27T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-28T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-29T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-30T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-31T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-01T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-02T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-03T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-04T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-05T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-06T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-07T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-08T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-09T23:00:00.000Z } ]

按连续日期分组的数组，如：

[ [ { state: 'BOOKED', date: 2017-01-01T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-02T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-03T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-04T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-05T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-06T23:00:00.000Z } ],
  [ { state: 'BOOKED', date: 2017-01-27T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-28T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-29T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-30T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-01-31T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-01T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-02T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-03T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-04T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-05T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-06T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-07T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-08T23:00:00.000Z },
  { state: 'BOOKED', date: 2017-02-09T23:00:00.000Z } ] ]

我现在发疯了。更新：

到目前为止我尝试了什么：

var _ = require('lodash');
var moment = require('moment');

var bookings = [
    {state: 'BOOKED', date: moment('2017-01-01T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-02T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-03T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-04T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-05T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-06T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-27T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-28T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-29T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-30T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-01-31T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-01T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-02T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-03T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-04T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-05T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-06T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-07T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-08T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-09T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-18T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-19T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-20T23:00:00.000Z')},
    {state: 'BOOKED', date: moment('2017-02-21T23:00:00.000Z')}
];

var ranges = {};
var range = 1;

_.each(bookings, function (booking, idx) {
    var next = idx + 1;

    if (!ranges[range]) {
        ranges[range] = [];
    }

    if (!bookings[next]) {
        return;
    }

    if (booking.date.clone().add(1, 'day').isSame(bookings[next].date)) {
        ranges[range].push(booking);
    } else {
        range++;
    }
});

哪种工作方式，但前提是数组内的对象的顺序正确。

Answer 1

您可以使用Array.reduce函数循环数据并匹配当前值和下一个值。

观

创建临时变量以保存先前的值，并使用临时数组保存当前组。
循环数据，每次迭代，检查当前值到临时变量的值。
如果差值为1，则将其推入临时数组。重置临时数组并将当前元素推入其中。
如果没有，并且临时数组有值，请在最终数组中推送临时数组。

示例代码

var data=[{state:"BOOKED",date:"2017-01-01T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-02T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-03T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-04T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-05T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-06T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-27T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-28T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-29T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-30T23:00:00.000Z"},{state:"BOOKED",date:"2017-01-31T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-01T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-02T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-03T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-04T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-05T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-06T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-07T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-08T23:00:00.000Z"},{state:"BOOKED",date:"2017-02-09T23:00:00.000Z"}];
  
var result = [];
var lastDate = null;
data.reduce(function(p, c, i, a){
	var date = new Date(c.date);
  if (!(lastDate === null || getDiffInDays(lastDate, date) === 1)){
  	result.push(p);
    p=[];
  }
  p.push(c)
  if(i === a.length - 1 && p.length > 0){
  	result.push(p);
  }
  lastDate = date;
  return p;
},[])

console.log(result)

function getDiffInDays(d1, d2){
	if(d1 && d2){
  	var milliSecInDay = 24 * 60 * 60 * 1000;
    return parseInt((+d2 - +d1)/milliSecInDay);
  }
}

将日期数组拆分为范围

1 个答案:

观

示例代码